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Alexxandr [17]
3 years ago
5

9+3.5g=11-0.5g brainliest to whoever gives steps

Mathematics
1 answer:
kow [346]3 years ago
7 0

Answer:

The answer is <u>g = 0.5</u>

Step-by-step explanation:

1. Your equation is :

<em>9+3.5g=11-0.5g</em>

2. First, multiply both sides by ten

<em>9 * 10 + 3.5 * 10 = 11 * 10 - 0.5 * 10</em>

3. Next we refine the equation

<em>90 + 35g = 110 - 5g</em>

4. Now, lets subtract 90 from both sides

<em>90 + 35g - 90 = 110 - 5g - 90</em>

5. Simplify

<em>35g + 5g = -5g + 20 + 5g</em>

6. We then add 5g to both sides

<em>35g + 5g = -5g + 20 + 5g</em>

7. Simplify again

<em>40g = 20</em>

8. Now, divide both sides by 40

<em>40g/40 = 20/40</em>

9. And finally, simplify once again to get your final answer.

<em>g = 1/2 or 0.5</em>

I hope this helped :)

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omega and r in terms of given data: 
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Thus: 
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What forces cause this acceleration for the passenger, at either top or bottom? 

At top (acceleration is downward): 
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Thus Newton's 2nd law reads: 
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At top (acceleration is upward): 
Weight (m*g): downward 
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Thus Newton's 2nd law reads: 
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Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame: 
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Substitute a: 
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Nbottom = m*(g + 2*Pi^2*d/T^2) 

We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground): 
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g) 
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g) 

Simplify: 
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2) 
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2) 

Data: 
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Results: 
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Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
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<u />

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