2 years ago

What are prime Numbers

Mathematics

2 answers:

Eva8 [605]2 years ago

6 0

Numbers that can only be mulitplied by 1 and itself. So 3 is a prime number. nothing else besides 1*3= 3

KiRa [710]2 years ago

5 0

2,3,5,7,11,13,821, and 823

please can i have a brainliest

You might be interested in

Help Please (I needed 20 characters)

liq [111]

Is a (0,18) ? not sure though baha.

4 0

2 years ago

Please PLEASE HELP ASAP EVERYONE KEEPS PUTTING ABSURD STUFF PLEASEE

levacccp [35]

domain 100 is the answer

3 0

2 years ago

The berry-picking boxes at Bingo Berry Farm have square bottoms that are 8 centimeters on each side. Santiago fills his box with

Pie

You can solve this by doing 8×8×6 which gives you 384. Since we are finding the volume, you would do length times with times height. Hope this helps :-)

6 0

2 years ago

30.5 $ with a 5% tax rate

Vlad [161]

Answer:

$32.03

Step-by-step explanation:

Since there is a tax rate, you want to multiply $30.50 by 1.05 since you are adding tax to it and it is 5%. You should get 32.025 as the result, but since you need to round it, it is $32.03.

4 0

2 years ago

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

6 0

2 years ago