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Angelina_Jolie [31]
3 years ago
12

Consider the line -x+3y=1

Mathematics
1 answer:
deff fn [24]3 years ago
6 0
The line
<span>-x+3y=1 can be moved into slope intercept form to get slope.
slope is what matters for questions that asks about perpendicular/parallel...

isolate y to get slope intercept form

</span>
<span>-x+3y=1
add x to both sides
3y = x + 1
divide both sides by 3
y = (x+1)/3
y = x/3 + 1/3

the slope is 1/3 because x/3 is the same as 1/3 * x.

the line that is perpendicular to this line has a slope that is the negative recirpocal of the original slope like.

perpendicular line slope: -3. (reciprocal of 1/3 is 3; then make that negative).

Told that this perp line passes through (7,-5), using slope intercept form y = mx + b with unknown y-intercept b value:

y = -3x + b

since (7,-5) means at x = 7, y = -5, plug those numbers in to solve for b

-5 = -3(7) + b
-5 = -21 + b
b = -5 + 21
b = 16

perpendicular line:
y = -3x + 16

for the parallel line has the same slope as the original
slope of parallel line: 1/3

we are told that parpall line goes through (7,-5) so using the unfinished slope-intercept form y = mx + b with unfinishe dinfo: we have

y = 1/3 x + b

since at x = 7 we have y = -5, plug it in

-5 = (1/3)(7) + b
-5 = 7/3 + b
b = -5 - 7/3
b = -15/3 - 7/3 .... same denominator for fraction add/subtract
b = -22/3

parallel line equation:
y = 1/3x - 22/3
</span>
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En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

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victus00 [196]

The answer would be...

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