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bearhunter [10]
3 years ago
14

at a sale search were sold for $15 each. This price was 80% of the original price. What was the original price?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
5 0
Let's say the original price was "x", thus "x" is the 100%, and we know that 15 is 80% of that, thus

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
x&100\\
15&80
\end{array}\cfrac{x}{15}=\cfrac{100}{80}\implies x=\cfrac{1500}{80}
vichka [17]3 years ago
5 0
The original price was $75.

$15 would be 1/5 (80%) of an uknown number, which is stated in the question. Since it's 1/5, you would multiply 15 by 5, to get 5/5 (100%), which is the original price. To check this, you would take 80% percent from 75 (0.8*75), which gives you 15. Thus proving $75 dollars was the original price.

I hope this helps!
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3 years ago
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Which equation shows 4n = 2(+ - 3) solved for T?
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C. T = 4n+6/2

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or, 4n = 2T-6

or, 4n + 6 = 2T

or, 4n + 6 / 2 = T

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2 years ago
What is the slope of the line described by the equation below?
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Answer:

D. 3

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

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<u>Step 2: Break Function</u>

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3 0
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4 years ago
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√13=not a natural number

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√21=not a natural number

√43=not a natural number

√48=4√3=not a natural number

√23=not a natural number

√39=not a natural number

√45=3√5=not a natural number

So, out of following numbers 13 27 81 21 43 48 23 39 45→81 is the only square number.

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