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bearhunter [10]
3 years ago
14

at a sale search were sold for $15 each. This price was 80% of the original price. What was the original price?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
5 0
Let's say the original price was "x", thus "x" is the 100%, and we know that 15 is 80% of that, thus

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
x&100\\
15&80
\end{array}\cfrac{x}{15}=\cfrac{100}{80}\implies x=\cfrac{1500}{80}
vichka [17]3 years ago
5 0
The original price was $75.

$15 would be 1/5 (80%) of an uknown number, which is stated in the question. Since it's 1/5, you would multiply 15 by 5, to get 5/5 (100%), which is the original price. To check this, you would take 80% percent from 75 (0.8*75), which gives you 15. Thus proving $75 dollars was the original price.

I hope this helps!
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