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Elodia [21]
3 years ago
10

A philanthropic organization helped a town in Africa dig several wells to gain access to clean water. Before the wells were in p

lace, an average of 120 infants contracted typhoid each month. After the wells were installed, the philanthropic organization surveyed for four months and found an average of 90 infants contracted typhoid per month. Assume that the population standard deviation is 40 and the number of infants that contract typhoid is normally distributed. Calculate the value of the appropriate test statistic.
Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer: -1.5

Step-by-step explanation:

When population standard deviation is known, then the formula to find the z-test statistic for population mean is given by :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

, where n= Sample size.

\mu = Population mean

\overline{x} = Sample mean

\sigma= Population standard deviation.

As per  given , we have \mu=120 (average infants contracted typhoid each month)

\sigma=40

n= 4 (No. of months)

\overline{x}=90

Then , the value of the appropriate test statistic will be :

z=\dfrac{90-120}{\dfrac{40}{\sqrt{4}}}

z=\dfrac{-30}{\dfrac{40}{2}}

z=\dfrac{-30}{20}

z=-1.5

Hence, the value of the test statistic = -1.5

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We conclude that the null hypothesis is rejected which means residents of Legacy Ranch use less water on average.

Step-by-step explanation:

We are given that the American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day.

Twenty-three owners responded, and the sample mean water use per day was 63 gallons with a standard deviation of 8.1 gallons per day.

<u><em>Let </em></u>\mu<u><em> = average water usage by residents of Legacy Ranch.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 67 gallons     {means that the residents of Legacy Ranch uses more or equal to 67 gallons water on average}

Alternate Hypothesis, H_A : \mu < 67 gallons    {means that the residents of Legacy Ranch use less water on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                                 T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean water use per day = 63 gallons

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So, <u><em>test statistics</em></u>  =  \frac{63-67}{\frac{8.1}{\sqrt{23} } }  ~ t_2_2

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The value of the test statistics is -2.368.

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Therefore, we conclude that the residents of Legacy Ranch use less water on average.

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