Answer: The answer is ![(x+7)(3x+1)=33x^2+22x+7.](https://tex.z-dn.net/?f=%28x%2B7%29%283x%2B1%29%3D33x%5E2%2B22x%2B7.)
Step-by-step explanation: Given that
![(3x2 + 22x + 7) \div(x + 7) = 3x + 1,](https://tex.z-dn.net/?f=%283x2%20%2B%2022x%20%2B%207%29%20%5Cdiv%28x%20%2B%207%29%20%3D%203x%20%2B%201%2C)
and we are to complete the following sentence:
![(x+7)(???)=???](https://tex.z-dn.net/?f=%28x%2B7%29%28%3F%3F%3F%29%3D%3F%3F%3F)
We have the following division algorithm for polynomials
![\textup{If }a(x)\times b(x)=c(x),\\\textup{then, we have }\\\\\dfrac{c(x)}{b(x)}=a(x)~~~~~\textup{or}~~~~~~c(x)\div b(x)=a(x).](https://tex.z-dn.net/?f=%5Ctextup%7BIf%20%7Da%28x%29%5Ctimes%20b%28x%29%3Dc%28x%29%2C%5C%5C%5Ctextup%7Bthen%2C%20we%20have%20%7D%5C%5C%5C%5C%5Cdfrac%7Bc%28x%29%7D%7Bb%28x%29%7D%3Da%28x%29~~~~~%5Ctextup%7Bor%7D~~~~~~c%28x%29%5Cdiv%20b%28x%29%3Da%28x%29.)
Here, a(x) = quotient, b(x) = divisor and c(x) = dividend.
Applying this rule in the given problem, we have
![\textup{since }(3x2 + 22x + 7) \div(x + 7) = 3x + 1,\\\\\textup{so, }\\\\(x+7)(3x+1)=3x^2+22x+7=0.](https://tex.z-dn.net/?f=%5Ctextup%7Bsince%20%7D%283x2%20%2B%2022x%20%2B%207%29%20%5Cdiv%28x%20%2B%207%29%20%3D%203x%20%2B%201%2C%5C%5C%5C%5C%5Ctextup%7Bso%2C%20%7D%5C%5C%5C%5C%28x%2B7%29%283x%2B1%29%3D3x%5E2%2B22x%2B7%3D0.)
Thus, the complete sentence is
![(x+7)(3x+1)=3x^2+22x+7=0.](https://tex.z-dn.net/?f=%28x%2B7%29%283x%2B1%29%3D3x%5E2%2B22x%2B7%3D0.)
Answer:
1/2 and 3
Step-by-step explanation:
The quadratic formula is as given:
( -b±√(b^2-4ac) )/2a
To use it, plug in the a,b and c values.
ax^2+bx+c
In this case a is equal to 2, b is equal to -7, and c is equal to 3
plugging it into our formula gives us:
(-(-7)±√(-7^2-4*2*3) )/2*2
Which is equal to:
7±√(49-24) / 4
= 7±√25 / 4
=7±5 / 4
=2/4, 12/4= 1/2, 3
164 sq. Meters is the area of the figure
To the hundredth place, or second decimal this would be 1.004_
So this will become 1.0
Answer:
=8v9g(x)
Step-by-step explanation: