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lana [24]
3 years ago
8

Find the infinite sum of 10,5,2.5,1.25...

Mathematics
2 answers:
scZoUnD [109]3 years ago
8 0
To the risk of sounding redundant.

notice it goes from 10, to 5, to 2.5 and so forth, the next term is half the previous one, namely the multiplier, or "common ratio" is 1/2.

10 * 1/2 is 5, 5 * 1/2 is 2.5 and so on.

now, the Sum is going to infinity, however, when the common ratio is a fraction less than 1 and more than 0, either negative or positive, it is convergent, namely it reaches a limit, it doesn't go to neverland.

so, in this case, the common ratio is indeed | r | < 1, and therefore, it does reach a limit, keeping in mind the first term's value is 10.

\bf \textit{Sum of an infinite sequence}\\\\&#10;S=\sum\limits_{i=0}^\infty~a_1\cdot r^i,\quad |~r~|~
____ [38]3 years ago
3 0
Notice this is a geometric progression since each number multiplied by some factor equals the next number in the sequence, in this case,

10 \times r = 5 \Rightarrow r=0.5

Then by applying the formula for sum to infinity of a geometric progression,
S_\infty = \frac{a}{1-r} = \frac{10}{1-0.5} = 20
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For every 1 litre of water used to make a medicine, 193ml of sucrose and 61ml of saline solution are used. Express the amount of
Brilliant_brown [7]
<h3>Answer is the ratio 1000:193:61</h3>

Explanation

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For every 1000 mL of water, we need 193 mL of sucrose and 61 mL of saline solution.

The ratio is therefore 1000:193:61

We cannot simplify this ratio any further because the GCF of those three terms is 1.

A quick way to see this is to look at how 1000 = (2*5)^3 has prime factors 2 and 5, but 2 nor 5 are factors of 193 and 61. So only 1 is a factor of all three values 1000, 193, 61

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