Answer:
x = all real numbers, infinite solutions
Step-by-step explanation:
4(x-2) + 7 = 4x - 1
Distribute
4x -8+7 = 4x-1
Combine like terms
4x -1 = 4x-1
Subtract 4x from each side
4x-1 -4x = 4x-1-4x
-1 = -1
This is always true so there are infinite solutions for x
Answer:
2441.95 years
Step-by-step explanation:
We can model this exponencial function as:
P = Po * (1+r)^(t/n)
Where P is the final value, Po is the inicial value, r is the rate, t is the time and n is the period of half-life.
In this case, we have that P/Po = 100% - 25.5% = 74.5% = 0.745, r = -0.5 and n = 5750, so we have that:
0.745 = (1 - 0.5)^(t/5750)
Step 1: log in both sides:
log(0.745) = (t/5750) * log(0.5)
Step 2: isolate t
t = 5750*log(0.745)/log(0.5) = 2441.95 years
Answer:
<em>Mr. Allen will need 28 oz. of preserver</em>
Step-by-step explanation:
<u>Proportions</u>
A direct proportion is a relation between variables where their ratio is a constant value. This means that if p and g are proportional, then:
p = kg
Where k is the constant of proportionality.
Where p is the quantity of preserver Mr. Allen needs to store his boat for winter, and g is the gallons of gas of the tank.
We are already given the ratio of fuel preserver and gallons of gas as 1 oz:2.5 gallons.
The value of k is, then k=1/2.5. The proportion is written as:
p = g/2.5
Since the boat holds g=70 gallons of gas:
p = 70/2.5 = 28
Mr. Allen will need 28 oz. of preserver
Answer:
0.2036
Step-by-step explanation:
u = arcsin(0.391) ≈ 23.016737°
tan(u/2) = tan(11.508368°)
tan(u/2) ≈ 0.2036
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You can also use the trig identity ...
tan(α/2) = sin(α)/(1+cos(α))
and you can find cos(u) as cos(arcsin(0.391)) ≈ 0.920391
or using the trig identity ...
cos(α) = √(1 -sin²(α)) = √(1 -.152881) = √.847119
Then ...
tan(u/2) = 0.391/(1 +√0.847119)
tan(u/2) ≈ 0.2036
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<em>Comment on the solution</em>
These problems are probably intended to have you think about and use the trig half-angle and double-angle formulas. Since you need a calculator anyway for the roots and the division, it makes a certain amount of sense to use it for inverse trig functions. Finding the angle and the appropriate function of it is a lot easier than messing with trig identities, IMO.
Answer:
What?
Step-by-step explanation: