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3 years ago

What is the answer please answer fast

Mathematics

1 answer:

svlad2 [7]3 years ago

4 0

Answer:

see the attachment

Step-by-step explanation:

First of all, we need to figure out which "category" each observation belongs to. Then we need to count the number of observations in each category and enter that count in the table.

I have numbered the categories 1-4 from top to bottom so that you can see how I have assigned observations to categories. The numbers on the right in the table are the ones the problem is asking for. (6, 2, 3, 3)

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How is the quotient of 3,419 and 11 determined using an area model? Enter your answers in the boxes to complete the equations. 3

Ipatiy [6.2K]

The quotient of 3,419 and 11 is 310.81.

<h3>How to illustrate the information?</h3>

It should be noted that from the information given, we are to find the quotient of 3,419 and 11 determined using an area model.

It should be noted that this simply means the division of the values given. This will be:

= 3419/11

= 310.81

Therefore, the quotient of 3,419 and 11 is 310.81.

Learn more about quotient on:

brainly.com/question/11916238

#SPJ1

6 0

1 year ago

For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp

Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

$\frac{1}{365}$

a) Probability that exactly 3 people have same birthday = $\frac{1}{365^3}$

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = $\frac{1}{365^3}$

Expected value of days = np = $\frac{1}{365^2}$

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0

4 years ago

Points giveaway<br><br>2+3=?

Nata [24]

Answer:

Step-by-step explanation:

Hence it is correct.. thanks for points.

5 0

2 years ago

Read 2 more answers

#10 AH IM STUCK ON THIS ITS HARD HELP

Dafna11 [192]

Answer:

4.8 in

Step-by-step explanation:

feet to inch conversion is *12

2 * 12 = 24

then divide the scale (for every 1 in on the model there is 5 in on the actual, so divide the actual value by 5)

24/5 = 4.8

your answer is 4.8 in

hope this helps:)

6 0

2 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

3 years ago