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Nikolay [14]
3 years ago
9

A point is randomly selected on the grid. What is the

Mathematics
2 answers:
VLD [36.1K]3 years ago
4 0

Answer:

13/24

Step-by-step explanation:

I got it right.

kicyunya [14]3 years ago
3 0

Answer:

the answer is 13/24 just did it

Step-by-step explanation:

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The graph shows:
irina1246 [14]

Answer:

Negative slope.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A person has a loan balance of $3083.86 on the new 23-inch rims and tires he bought for his SUV. If his payments are $106.34 per
dusya [7]
3038.86 / 106.34 = 29

29 months

6 0
2 years ago
Anyone good with algebra 2??
sweet [91]
A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.

Let's look at your function.

f(x) = \dfrac{x^2 - 16}{6x - 24}

x^2 - 16  is in the numerator. It is defined for every value of x. There is no problem there.

6x - 24  is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.

We set it equal to zero and solve the equation for x.

6x - 24 = 0

6x = 24

x = 4

For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).

The answer is:

x \ne 4

6 0
3 years ago
2y-x=2 substitute solution?
DerKrebs [107]

Answer:

Y=1 X=0

Step-by-step explanation:

5 0
3 years ago
What is the amplitude of sin ?
sp2606 [1]

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

\displaystyle \large{ y = A \sin(bx  -  c) + d}

  • A = amplitude
  • b = period = 2π/b
  • c = horizontal shift
  • d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

\displaystyle \large{y = 2 \sin x}

Refer to the equation above:

  • Amplitude = 2
  • b = 1 and therefore, period = 2π/1 = 2π
  • c = 0
  • d = 0

Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

6 0
3 years ago
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