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Nikolay [14]
3 years ago
9

A point is randomly selected on the grid. What is the

Mathematics
2 answers:
VLD [36.1K]3 years ago
4 0

Answer:

13/24

Step-by-step explanation:

I got it right.

kicyunya [14]3 years ago
3 0

Answer:

the answer is 13/24 just did it

Step-by-step explanation:

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Select the correct answer,
o-na [289]

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C. 60

Step-by-step explanation:

60+10=70

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Keegan and Annie are working on an experiment in the science lab. Their mixture contains ingredients that weigh 5.22 grams, 5.7
Elza [17]

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C

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3 years ago
jada and diego are practing the piano for sn upcoming rehersal the table list the number of minutes each of them practiced in th
Margarita [4]

Answer:

jadas practice time is 168 minutes or 2 hours 48 minutes.  Diegos practice time is 235 minutes or 3 hours 55minutes hope this helps! have a nice day and good luck with your test!

Step-by-step explanation:

4 0
2 years ago
2 2/3 + 12 6/8 how do I work this
barxatty [35]

Answer:

\large\boxed{2\dfrac{2}{3}+12\dfrac{6}{8}=15\dfrac{5}{12}}

Step-by-step explanation:

2\dfrac{2}{3}+12\dfrac{6}{8}=2\dfrac{2}{3}+12\dfrac{6:2}{8:2}=2\dfrac{2}{3}+12\dfrac{3}{4}\\\\\text{Find}\ LCD:\\\\\text{List of multiples of 3:}\ 0,\ 3,\ 6,\ 9,\ \boxed{12},\ 15,\ ...\\\text{List of multiples of 4:}\ 0,\ 4,\ 8,\ \boxed{12},\ 16,\ ...\\\\12=3\cdot4\\\\\text{therefore}\\\\\dfrac{2}{3}=\dfrac{2\cdot4}{3\cdot4}=\dfrac{8}{12}\\\\\dfrac{3}{4}=\dfrac{3\cdot3}{4\cdot3}=\dfrac{9}{12}\\\\2\dfrac{2}{3}+12\dfrac{3}{4}=2\dfrac{8}{12}+12\dfrac{9}{12}=(2+12)+\dfrac{8+9}{12}=14+\dfrac{17}{12}\\\\=14+1\dfrac{5}{12}=15\dfrac{5}{12}

3 0
3 years ago
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
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