Answer: ![\sqrt[]{\frac{1}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
Step-by-step explanation:
![x=\frac{1}{9}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B9%7D)
![\sqrt[]{3x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3x%7D)
![\sqrt[]{3(\frac{1}{9}) }](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%28%5Cfrac%7B1%7D%7B9%7D%29%20%7D)
![\sqrt[]{\frac{1}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
Function 1 is a constant function
.. y = 2
Function 2 has the value 3 at x=0.
3 is greater than 2, so Function 2 has the greater initial value.
so it is compounded 4 times in a year in 4 years we can take it as 16 terms
a=6700(1+3.3/100)^16
a=6700(1+33/1000)^16
a=6700(1000/1000 + 33/1000)^16
a=6700(1.033)^16
a=6700*1.681144887891022
a=6700*1.6811
a=11263.23
Answer:
i need help please with my maths
Step-by-step explanation: