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olga55 [171]
4 years ago
14

What is the slope to the equation (2,1) (-1,-2)

Mathematics
2 answers:
kipiarov [429]4 years ago
8 0
(2y,1x) do u get it or am i not helping sorry if this doesnt help

Alenkinab [10]4 years ago
5 0
Okay,

this is the formula that i use

y2-y1/x2- x1

plug it in so it is going to be

-2 - 1             -3
______ =      ____ = a (-) divided by a (-) is a (+)  so the answer is 1 

-1 - 2              -3
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6 0
3 years ago
Independent random samples of vehicles traveling past a given point on an interstate highway have been observed on monday versus
quester [9]
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To compare this two sets of data, you need to use a t-student test:

You have the following data:

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-Wednesday n2=20;  </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



5 0
4 years ago
Which is bigger 3 yards is 10 feet
77julia77 [94]
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3 yards = 3 * 3 = 9 feet

9 feet < 10 feet

Hope that helped =)
5 0
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VARVARA [1.3K]

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3 years ago
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Answer:

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hope it helps

3 0
3 years ago
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