Answer:
3 ln(x − 1) − 3/(x − 1) + C
Step-by-step explanation:
∫ 3x / (x − 1)² dx
3 ∫ x / (x − 1)² dx
If u = x − 1, then x = u + 1, and du = dx.
3 ∫ (u + 1) / u² du
3 ∫ (1/u + 1/u²) du
3 (ln u − 1/u + C)
3 ln u − 3/u + C
Substitute back:
3 ln(x − 1) − 3/(x − 1) + C
28 teachers prefer mint.
Step-by-step explanation:
Given,
Total number of teachers = 98
Ratio of teacher that prefer rocky road to mint = 5:2
Let,
x be the original number.
Teachers who like rocky road = 5x
Teachers who like mint = 2x

Dividing both sides by 7

Teachers who prefer mint = 2x = 2(14) = 28
28 teachers prefer mint.
Keywords: ratio, division
Learn more about division at:
#LearnwithBrainly
Answer:
Option D.
Step-by-step explanation:
- First, the you need ti understand that the triangle is an isosceles right angled triangle. In other words, the base and height are equal in length. The third side is the slide. This is the longest side.
- Next, we know that the formula for calculating the area of a right angled triangle is given by:
A = 1/2 (base × perpendicular height)
- The perpendicular height is equal to the base. Let's say the base is <em>x</em>. It means that the height is also x, since height = base.
- Therefore, the formula will be:
A = 1/2 (x.x)
=1/2 (x²)
32 = 1/2 (x²)
Multiplying both sides by 2 gives:
32×2 = x²
64 = x²
8 = x
To find the third side, we use the Pythagoras theorem:
C² = A² + B²
= 8² + 8²
= 128
C = √128
= 8√2
However, the answer will not be exact, so we multiply the length of the base and height by 2. This gives x = 16 (Length of base = length of height)
Repeating the steps above gives C = √ (16)² + (16)²
= √256
This corresponds to option D.
Ooh, fun
what I would do is to make it a piecewise function where the absolute value becomse 0
because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up
so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points
we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5
A.

B.
sepearte the integrals
![\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E%7B-5%7D_%7B-4%7D%20%7Bx%5E2%2Bx-12%7D%20%5C%2C%20dx%20%3D%20%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%2B%5Cfrac%7Bx%5E2%7D%7B2%7D-12x%5D%5E%7B-5%7D_%7B-4%7D%3D%28%5Cfrac%7B-125%7D%7B3%7D%2B%5Cfrac%7B25%7D%7B2%7D%2B60%29-%28%5Cfrac%7B64%7D%7B3%7D%2B8%2B48%29%3D%5Cfrac%7B23%7D%7B6%7D)
next one
![\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E%7B-4%7D_3%20%7B-x%5E2-x%2B12%7D%20%5C%2C%20dx%3D-1%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%2B%5Cfrac%7Bx%5E2%7D%7B2%7D-12x%5D%5E%7B-4%7D_%7B3%7D%3D-1%28%28-64%2F3%29%2B8%2B48%29-%289%2B%289%2F2%29-36%29%29%3D%5Cfrac%7B343%7D%7B6%7D)
the last one you can do yourself, it is

the sum is

so the area under the curve is
<span>$2,500.00 would be your answer
</span>