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Scorpion4ik [409]
3 years ago
13

Angela is plowing a large field for spring planting. On the first day, she plowed 2/7 of the field. On the second day, she plowe

d 2/3 of the field.
What fraction of the field is Not plowed at the end of the second day?

A) 1/21
B) 4/21
C) 17/21
D) 20/21​
Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0

Answer:

A) 1/21

Step-by-step explanation:

<u>2</u> + <u>2</u> is hard to do without making the denominators equal first.

7    3 you can multiply the fractions until the denominators are equal.

<u>6 </u> + <u>14</u> = <u>20</u>

21   21     21

now that this is done, the answer is as simple as looking at how much is left until a whole is completed. this will be A) 1/21

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Graph the following inequality and then select the correct graph below. x - y - 2 ≥ 0
-Dominant- [34]

Answer:

the graph in the attached figure

Step-by-step explanation:

we have

x-y-2\geq 0

Isolate the variable y

-y\geq -x+2 -----> Multiply by -1

y\leq x-2

The solution of the inequality is the shaded area below the solid line

The equation of the line is y= x-2

The slope of the line is positive

The y-intercept of the line is the point (0,-2)

The x-intercept of the line is the point (2,0)

Using a graphing tool

the graph in the attached figure

7 0
3 years ago
Read 2 more answers
Police Chase: A speeder traveling 40 miles per hour (in a 25 mph zone) passes a stopped police car which immediately takes off a
zubka84 [21]

Answer:

a. 18.34 s b. 327.92 m

Step-by-step explanation:

a. How long before the police car catches the speeder who continued traveling at 40 miles/hour

The acceleration of the car a in 10 s from 0 to 55 mi/h is a = (v - u)/t where u = initial velocity = 0 m/s, v = final velocity = 55 mi/h = 55 × 1609 m/3600 s = 24.58 m/s and t = time = 10 s.

So, a =  (v - u)/t =  (24.58 m/s - 0 m/s)/10 s = 24.58 m/s ÷ 10 s = 2.458 m/s².

The distance moved by the police car in 10 s is gotten from

s = ut + 1/2at² where u = initial velocity of police car = 0 m/s, a = acceleration = 2.458 m/s² and t = time = 10 s.

s = 0 m/s × 10 s + 1/2 × 2.458 m/s² (10)²

s = 0 m + 1/2 × 2.458 m/s² × 100 s²

s = 122.9 m

The distance moved when the police car is driving at 55 mi/h is s' = 24.58 t where t = driving time after attaining 55 mi/h

The total distance moved by the police car is thus S = s + s' = 122.9 + 24.58t

The total distance moved by the speeder is S' = 40t' mi = (40 × 1609 m/3600 s)t' =  17.88t' m where t' = time taken for police to catch up with speeder.

Since both distances are the same,

S' = S

17.88t' = 122.9 + 24.58t

Also, the time  taken for the police car to catch up with the speeder, t' = time taken for car to accelerate to 55 mi/h + rest of time taken for police car to catch up with speed, t

t' = 10 + t

So, substituting t' into the equation, we have

17.88t' = 122.9 + 24.58t

17.88(10 + t) = 122.9 + 24.58t

178.8 + 17.88t = 122.9 + 24.58t

17.88t - 24.58t = 122.9 - 178.8

-6.7t = -55.9

t = -55.9/-6.7

t = 8.34 s

So, t' = 10 + t

t' = 10 + 8.34

t' = 18.34 s

So, it will take 18.34 s before the police car catches the speeder who continued traveling at 40 miles/hour

b. how far before the police car catches the speeder who continued traveling at 40 miles/hour

Since the distance moved by the police car also equals the distance moved by the speeder, how far the police car will move before he catches the speeder is given by S' = 17.88t' = 17.88 × 18.34 s = 327.92 m

4 0
3 years ago
Use substitution to find the solution to the system of equations.
mote1985 [20]

Answer:

Ummm, so the answer is A. (-3,-2)

StepByStep Solution:

5x + 7(x+1) =-29

5x+7x+7=-29

12x=-36

x=-3

y=-3+1

y=-2

4 0
3 years ago
Read 2 more answers
Determine the area bounded by the curves f(x) = 4x and g(x) = 3x + 1.​
ANEK [815]

Answer: 12x^2+4

Step-by-step explanation:

7 0
3 years ago
If you graph both sides of the equation 2(2x+3) = 4x+6, what will the graph look like
TiliK225 [7]
<span>The graphs are identical and intersect at infinitely many points.

</span>
8 0
3 years ago
Read 2 more answers
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