Answer:
1,809.98 lb*m/s^2
Step-by-step explanation:
First, we want to know how much weight of the boulder is projected along the path in which the boulder can move.
The weight of the boulder is:
W = 322lb*9.8 m/s^2 = (3,155.6 lb*m/s^2)
This weight has a direction that is vertical, pointing downwards.
Now, we know that the angle of the hill is 35°
The angle that makes the direction of the weight and this angle, is:
(90° - 35°)
(A rough sketch of this situation can be seen in the image below)
Then we need to project the weight over this direction, and that will be given by:
P = W*cos(90° - 35°) = (3,155.6 lb*m/s^2)*cos(55°) = 1,809.98 lb*m/s^2
This is the force that Samuel needs to exert on the boulder if he wants the boulder to not roll down.
The value of the expression (2)^6 is 64.
Neither point is on either function.
f(x) reflected over the x-axis is
y=-10 + x
First you need to solve for angle F then you can use 1/2acSinB. If you haven't done this you can also use the Pythagoras theorem and solve for the unknown side once you do that you can just use 1/2 b*h
Answer:
Options (2), (4) and (5)
Step-by-step explanation:
Option (1).
Planes S contains points B and F.
False.
(Point B lies on plane S and point F lies on plane R)
Option (2).
The line containing points A and B lie on the plane T.
True.
(points A and B lie on plane T)
Option (3).
Line v intersects lines x and y at the same plane.
False.
Option (4).
Line z intersects plane S at point C.
True.
Option (5).
Planes R and T intersect at line y.
True.