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Fudgin [204]
3 years ago
6

Read the sentence from the first paragraph of Silent

Computers and Technology
2 answers:
Illusion [34]3 years ago
4 0

Answer: b. Peaceful is right

Explanation: trust me I just got 100% on the test :)

kakasveta [241]3 years ago
3 0

Answer:

B, Peaceful

Explanation:

Trust me, im 1000% sure that it is B.

I know hat you are probably already done with the test, but here you go anyway!

PLEASE mark me most brainly?!

You might be interested in
Build three classes that conform to the following interfaces. Use arrays in creating your classes (e.g., do not use the built-in
daser333 [38]

Explanation:

public class ArrayList {

private Object[] array = new Object[1];

/**

 * Places new element at location

 * @param c, element to be inserted

 * @param i, location it is to be placed

 */

public void insert(char c, int i) {

 if(i>this.size()){

  System.out.println("Index "+i +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(i){

     case 0:{

      other[0] = c;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<i;j++)

       other[j] = this.array[j];

      other[i] = c;

      for(int k=i+1;k<this.array.length;k++)

       other[k] = this.array[k-1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Places new element at location

 * @param object, element to be inserted

 * @param index, location it is to be placed

 */

void insert(Object object, int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(index){

     case 0:{

      other[0] = object;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      other[index] = object;

      for(int k=index+1;k<this.array.length;k++)

       other[k] = this.array[k];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Removes element at index

 * @param index, location to remove

 * @return temp, object removed

 */

Object remove(int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 Object temp = this.array[index];

 int count = 0;

 try {

  Object[] other = new Object[this.array.length-1];

  switch(index){

     case 0:{

      other[0] = this.array[1];

      for(int j=1;j<this.size();j++)

       other[j] = this.array[j+1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      for(int k=index;k<this.size();k++)

       other[k] = this.array[k+1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

 return temp;

}

 

/**

 * Copies the array to a new array twice the size.

 */

public void largerArray(){

 Object[] other = new Object[this.array.length*2];

 System.arraycopy(this.array, 0, other, 0, this.array.length);

 this.array = other;

}

 

/**

 * @return true if there are null elements

 */

public boolean isEmpty() {

 boolean bool = true;

 for (Object element : this.array) {

  if(element!=null){

   bool = false;

   break;

  }

  else{

   bool = true;

   break;

 }

 }

 return bool;

}

 

/**

 * Determines the real length of the array

 * @return length of non-null elements

 */

public int size(){

 int count = 0;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==null)

   continue;

  else

   count++;

 }

 return count;

}

 

/**

 * Converts array to string.

 * @return the Array as a string

 */

public String toString(){

 String string = "";

 for(int i=0;i<this.size();i++){

  if(i<this.size()-1)

   string += this.array[i]+", ";

  else

   string += this.array[i];

 }

 return string;

}

 

/**

 * Similar to get, imput the character, retrieve index.

 * @param object, what we're looking for

 * @return index

 */

int indexOf(Object object){

 int index = -1;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==(object))

   index = i;

  else continue;

 }

 return index;

}

 

/**

 * @param object, Arraylist tyoe

 * @return true, if the elements of the arrays are equivalent.

 */

public boolean equals(ArrayList object){

 boolean bool = false;

 int thisLength = this.array.length;

 int objectLength = object.array.length;

 if(thisLength > objectLength){

  for(int i=0;i<this.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 else{

  for(int i=0;i<object.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 return bool;

}

 

/**

 * Getter to check what is at an index

 * @param index, location

 * @return the character at this position

 */

Object get(int index){

 return this.array[index];

}

}

6 0
3 years ago
3.5 Code Practice: Question 1 edhesive
klio [65]

Answer:

x = int(input("What grade are you in? "))

if(x == 9):

  print("Freshman")

 

elif(x == 10):

  print("Sophomore")

 

elif(x == 11):

  print("Junior")

 

elif(x == 12):

  print("Senior")

 

else:

  print("Not in High School")

Explanation:

4 0
3 years ago
All of the following are true about in-database processing technology EXCEPT Group of answer choices it pushes the algorithms to
vekshin1

All of the aforementioned are true about in-database processing technology except: D. it is the same as in-memory storage technology.

<h3>What is an in-database processing technology?</h3>

An in-database processing technology can be defined as a type of database technology that is designed and developed to allow the processing of data to be performed within the database, especially by building an analytic logic into the database itself.

This ultimately implies that, an in-database processing technology is completely different from in-memory storage technology because this used for the storage of data.

Read more on database here: brainly.com/question/13179611

#SPJ1

5 0
2 years ago
The term "resolution" refers to ______.
Usimov [2.4K]

Options A and C can get you confused. We can choose option A if our argument is based entirely on digital images. The correct answer, however, is  C: Number of pixels you see on your computer monitor.

Resolution describes the clarity and sharpness of a picture that can be measured by the number of pixels contained on a display monitor. It can be expressed by the number of horizontal (width) and vertical pixels (height) represented by a screen. The clarity and sharpness are always dependent on the resolution and size of the monitor.

4 0
3 years ago
Read 2 more answers
A computer has a pipeline with four stages. each stage takes the same time to do its work, namely, 1 nsec. how many instructions
prisoha [69]

In figuring, a pipeline, otherwise called an information pipeline, is a lot of information preparing components associated in arrangement

Further explanation:

In figuring, a pipeline, otherwise called an information pipeline, is a lot of information preparing components associated in arrangement, where the yield of one component is the contribution of the following one. The components of a pipeline are frequently executed in parallel or in time-cut style.

Instruction travelling:

999,999,997 guidelines for each second. The pipeline has 3 nsec of straightforward figurings, at that point finishes a guidance in each ensuing nsec.  

3nsec (for first guidance to go down the pipeline).10^9 ns every second. 10^9 – 3 = 999999997 directions.

Instruction per second:

MIPS - Million guidelines for each second  

Million guidelines for each second (MIPS) is a more established, outdated proportion of a PC's speed and power, MIPS measures generally the quantity of machine directions that a PC can execute in one second.

Per second:

Million directions for each second (MIPS) is a more established, old proportion of a PC's speed and power, MIPS measures generally the quantity of machine guidelines that a PC can execute in one second. Be that as it may, various directions require pretty much time than others, and there is no standard strategy for estimating MIPS. Moreover, MIPS alludes just to the CPU speed, while genuine applications are commonly constrained by different elements, for example, I/O speed

Answer Details:

Subject: Computer and technology

Level: College.

Key Words:

Further explanation:

Per second:

Instruction per second:

Instruction travelling:

For further Evaluation:

brainly.com/question/6362387

brainly.com/question/12938965

6 0
4 years ago
Read 2 more answers
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