In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for
a sample of 81 business students over a one-week period. Assume the population standard deviation is 1.8 hours.
The standard error of the mean is:
a) 7.50 b) 0.39 c) 2.00 d) 0.20
1 answer:
Answer: option D
Step-by-step explanation:
The formulae for standard error = standard deviation/√n
But population standard deviation = 1.8 and sample size = n = 81
Standard error = 1.8/√81 = 1.8/9 = 0.2
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Step-by-step explanation:
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9.125*x^2 is 100000 times greater than 9.125*10^(-3).
Note that (10^5)(9.125*10^(-3) = 9.125*10^2.
Answer:
30660
Step-by-step explanation:
For example:
(4/9) x=8
Now can solve this equation multiplying each side by 9/4.
(9/4)(4/9)x=(9/4)8
x=18
To check:
(4/9)(18)=(4*18)/9=72/9=8
