In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for
a sample of 81 business students over a one-week period. Assume the population standard deviation is 1.8 hours.
The standard error of the mean is:
a) 7.50 b) 0.39 c) 2.00 d) 0.20
1 answer:
Answer: option D
Step-by-step explanation:
The formulae for standard error = standard deviation/√n
But population standard deviation = 1.8 and sample size = n = 81
Standard error = 1.8/√81 = 1.8/9 = 0.2
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The pattern is that they are multiplying by -3 every time. 81*-3 = -243
Answer:
72
Step-by-step explanation:
12 6 times equals 72.
12x6=72
T+J=4 hours
x+2x=4 hours
3x=240 minutes
X=80 minutes
Answer:
1) 8
Step-by-step explanation:
3+2 is 5
4^2 is 16
16×5=80
2×5=10
80÷10=8
Since 7 is greater than 5, you input it into the last equation.
2•(7) -7
14-7
7
The answer is 7!
