because y^3 is raised to the power of two, we will have to multiply the exponents rather than adding them.
By distributing the power of 2, we will get y^2(6).
Because now the exponents are being multiplied, we can just add them to get y^8. The other y has a power of 1, so we'll just add the power of that y as well to get y^9.
summary:
multiply exponents if they are being raised to a power.
add exponents if they are being multiplied, and only add them if they have the same base (in this case, both the bases of the exponents are y, so we can add them)
For this question you can say:
154/11 = 252/?
so ? is the hours she would work:
252*11/154 = 18 hours :)))
i hope this is helpful
have a nice day
<span>we know that if 95 is out of 100%, we can write it down as 95 = 100%. w</span><span>e also know that x is 20% of the output value, so we can write it down as x = 20%. </span>
now we have the equations:
95=100%
x=20%
next we will put the equations together
95/x = 100%/20%
95/x=100/20
<span>(95/x)*x=(100/20)*x
</span>we multiply both sides of the equation by x
<span>95=5*x
</span>now we divide both sides of the equation by 5 to get x
<span>95/5=x </span>
<span>19=x </span>
x=19
we now know that <span>20% of 95 = 19
let me know if you have any other questions
:)</span>
First you would solve for h(5) by plugging in 5 as your x, then solving it.
h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26
Next you would multiply the 26 by the individual h, which is basically h(1).
h(1) = 1^2 + 1
h(1) = 2
Lastly you multiply your h(1) value by the h(5) value to get your answer.
h(1) • h(5) = 26 • 2
h[h(5)] = 52
