2/18 + 1 2/8 =
1/9 + 10/8 =
1/9 + 5/4 =
4/36 + 45/36 =
49/36 =
1 13/36 <==
Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Answer:
TOO SMALL I CanT SEE THE QUESTION!!
Step-by-step explanation:
Answer:
9/4 = 15/x
Multiply by x on both sides
9/4x = 15
Divide by 9/4
x = 60/9 or 6.6 repeated
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To estimate the sum or difference of 8/9 + 4/7 it should be <span>1 1/2
</span>It is also a way to find<span> an approximate answer to a solution. To </span>estimate<span> products and quotients of mixed numbers, round the </span>fractions<span> to the nearest whole number. If the </span>fraction<span> is less than 12 round down and if it is more than 12 round up. First, since 411 is less than 12,8411 rounds down to 8.</span><span>
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