41-28=13 questions, but you also have to do 41 and 28, so 15 questions
Step-by-step explanation:
There are four quarter circles, each with radius 9 ft. Together, they form a full circle. There are also four squares, each with side length 9 ft.
A = πr² + 4s²
A = π (9 ft)² + 4 (9 ft)²
A ≈ 578.469 ft²
Answer:
R3 <= 0.083
Step-by-step explanation:
f(x)=xlnx,
The derivatives are as follows:
f'(x)=1+lnx,
f"(x)=1/x,
f"'(x)=-1/x²
f^(4)(x)=2/x³
Simialrly;
f(1) = 0,
f'(1) = 1,
f"(1) = 1,
f"'(1) = -1,
f^(4)(1) = 2
As such;
T1 = f(1) + f'(1)(x-1)
T1 = 0+1(x-1)
T1 = x - 1
T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2
T2 = 0+1(x-1)+1(x-1)^2
T2 = x-1+(x²-2x+1)/2
T2 = x²/2 - 1/2
T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3
T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3
T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)
Thus, T1(2) = 2 - 1
T1(2) = 1
T2 (2) = 2²/2 - 1/2
T2 (2) = 3/2
T2 (2) = 1.5
T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)
T3(2) = 4/3
T3(2) = 1.333
Since;
f(2) = 2 × ln(2)
f(2) = 2×0.693147 =
f(2) = 1.386294
Since;
f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).
Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,
Since;
f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2
Finally;
R3 <= |2/(4!)(2-1)^4|
R3 <= | 2 / 24× 1 |
R3 <= 1/12
R3 <= 0.083
Answer:
120º
Step-by-step explanation:
angles of an equilateral triangle are equal so..
180 ÷ 3 = 60º
to get the exterior m⦣C
180 - interior m⦣C = exterior m⦣C
180º - 60º = 120º
He can give at most 2 adult haircuts with the remaining time
<h3>How many adult haircuts at most can he give with the remaining time? </h3>
The inequality is given as:
0.75C + 1.25A <= 7
Also, we have
C = 5
Substitute C = 5 in 0.75C + 1.25A <= 7
0.75 * 5 + 1.25A <= 7
Evaluate the product
3.75 + 1.25A <= 7
Evaluate the like terms
1.25A <= 3.25
Divide by 1.25
A <= 2.6
Rewrite as
A < 3
Hence, he can give at most 2 adult haircuts with the remaining time
Read more about inequalities at:
brainly.com/question/15010638
#SPJ1
<u>Complete question</u>
Horace is a professional hair stylist. Let C represent the number of child haircuts and A represent the number of adult haircuts that Horace can give within 7 hours. 0.75C + 1.25A <= 7
Horace gave 5 child haircuts.
How many adult haircuts at most can he give with the remaining time?
