3xy
<span>y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy </span>
<span>NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. </span>
<span>y(3y) + y(xy) + (y+1)(3x) </span>
<span>3y^2 + xy^2 + 3xy +3x </span>
<span>cannot simplify further.</span>
Answer:
Approximately 19.4%
Step-by-step explanation:
Co. Dogs: 13
Co. Others: 54
13+54=Total Co.
=67.
Co. Dogs: 13/67.
App. 19.4% (For 13 Co.)
App. 1.49% (For 1 Co.)
Answer:14708
Step-by-step explanation:Exponential Functions:
y=abxy=ab^x this is not right not correct
y=ab
x
a=starting value = 13000a=\text{starting value = }13000
a=starting value = 13000
r=rate = 2.5%=0.025r=\text{rate = }2.5\% = 0.025
r=rate = 2.5%=0.025
Exponential Growth:\text{Exponential Growth:}
Exponential Growth:
b=1+r=1+0.025=1.025b=1+r=1+0.025=1.025
b=1+r=1+0.025=1.025
Write Exponential Function:
y=13000(1.025)xy=13000(1.025)^x
y=13000(1.025)
x
Put it all together
Plug in time for x:\text{Plug in time for x:}
Plug in time for x:
y=13000(1.025)5y=13000(1.025)^{5}
y=13000(1.025)
5
y=14708.30677y= 14708.30677
y=14708.30677
Evaluate
y≈14708y\approx 14708
y≈14708
Answer:
the actual pressure is 31.09
Complete question:
What is the actual pressure when Ali's gauge shows 33.58
Step-by-step explanation:
Given,
Ali's tyre presser gauge show a reading 8% higher than the actual pressure.
Ali's gauge shows 33.58.
Let the actual pressure be x.
According to problem,
{ [If 8% increasing of a no ⇒ The number becomes = 
of the number}
x= 
x=31.09
Therefore, the actual pressure is 31.09
