1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
skelet666 [1.2K]
3 years ago
15

a circle has a radius of 15 centimeters and a central angle that measures 175 degrees. find the length of the arc defined by thi

s central angle. leave your answers in terms of pi. NEED ASAP
Mathematics
1 answer:
Harman [31]3 years ago
8 0

Answer:

14.58π cm to the nearest hundredth.

Step-by-step explanation:

Circumference of the circle = 2 π r

= 30π

By proportion the length of the arc defined by 175 degrees

= 30 π * 175 / 360

= 14.58 π cm.

You might be interested in
Sean bought a box of graham crackers for $3.99. He also bought 3 bags
leonid [27]
Answer:

$3.08

Explanation:

You subtract 3.99 from 13.23 which equals 9.24. Because there are three bags of marshmallows, divide 9.24 by 3, which equals $3.08.
4 0
3 years ago
Read 2 more answers
I will mark u as the brainliest I will mark u as the brainiest if u get this correct thx x
Elza [17]

Answer:

260

Step-by-step explanation:

The formula is base times height

7 0
2 years ago
Read 2 more answers
Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
Emile went out for dinner and received a bill for $32.45. He left an 18% tip How much
Hoochie [10]

Answer:

$38.29

Step-by-step explanation:

7 0
3 years ago
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
Other questions:
  • Simplify (-2V20k)(5v8K*) completely.
    8·2 answers
  • Factor the trinomial x^2+6x-16
    7·1 answer
  • 1/9 find the reciprocal
    7·2 answers
  • 2x6+8-1 can anyone help?
    8·2 answers
  • 6.52<br>65.2<br>0.652<br>order it least to greatest which comes first?​
    15·2 answers
  • Given the vertices of ∆ABC are A (2,-5), B (-4,6) and C (3,1), find the vertices following each of the transformations FROM THE
    13·1 answer
  • Which graph represents the equation y = --3x – 1?
    10·1 answer
  • a man owned 75 shares of stock worth $50 each the corporation declared a dividend of 8% payable in stock how many shares did he
    5·1 answer
  • Sam’s fish tank has a base area of 187 in2 and a height of 16
    7·1 answer
  • Please help me it’s really a struggle help help help
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!