Sine is the opposite to the hypotenuse
so if sinA=0.6, suppose the opposite is 6, the hypotenuse is 10
now find the other leg by using a²+b²=c²: 6²+b²=10², b=8
sinB=8/10=0.8
<h3>Given</h3>
a cuboid with length, width, height dimensions 5, 6, x
<h3>Find</h3>
the value of x that makes the numerical value of the total surface area equal to the numerical value of the volume
<h3>Solution</h3>
The volume is given by
... V = L·W·H = 5·6·x = 30x
The area is given by
... A = 2(L·W + H(L+W)) = 2(5·6 +x(5+6)) = 2(30 +11x) = 60 +22x
When these are equal, we have
... 30x = 60 +22x
... 8x = 60
... x = 7.5
The desired value of x is 7.5.
Answer: X = 7√2
Step-by-step explanation:
Let first Consider triangle BDC,
Cos C = adjacent/ hypothenus
Cos C = 7 / x ...... (1)
Also, let consider triangle ABC
Cos C = adjacent / hypothenus
Cos C = x / 14 ....... (2)
Since angle C is the same, equate equation 1 to 2
7/ x = x / 14
Cross multiply
X^2 = 98
Make x the subject of formula
X = sqrt (98)
X = sqrt ( 49 × 2 )
X = sqrt (49) × sqrt (2)
X = 7 sqrt(2)
X = 7√2
(5)(5)(5)(5)(5)(5)(5)(5)(5)(5)(5)
5^11
That is two of the three but I'm not quite sure if there is a third.
