1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rudik [331]
3 years ago
11

In 1945​, an organization asked 1490 randomly sampled American​ citizens, "Do you think we can develop a way to protect ourselve

s from atomic bombs in case others tried to use them against​ us?" with 770 responding yes. Did a majority of the citizens feel the country could develop a way to protect itself from atomic bombs in 1945​? Use the alpha equals 0.05 level of significance.
Mathematics
1 answer:
Schach [20]3 years ago
6 0

Answer:

1490/2= 745=50%  770>745 so  your answer is yes

Step-by-step explanation:

You might be interested in
5x6-1+3=28 brackets or braces should be added
Artyom0805 [142]
5 · (6 - 1) + 3
= 5·5 + 3
= 25 + 3
= 28
7 0
3 years ago
You earn $20.00 per hour at your job. If you get a 10% raise at the end of each year, what will your hourly rate, h, be after 8
love history [14]
R is the rate (10%)
C=20, begiing rate
T=time=8

so

h=20(1+0.10)^8
h=20(1.1)^8
h=42.8718
ronnd

$42.87


D is answer

4 0
3 years ago
Graph the function f(x) = 2√x +3.
Nikolay [14]

The graph is shown in the attached image.

8 0
2 years ago
The length of a rectangle is given by the function l(x)=2x+1, and the width of the rectangle is given by the function w(x)=x+4.
Harlamova29_29 [7]

Answer:

a(x)=2x^2+9x+4

Step-by-step explanation:

We have been given the length and width, as well as the formula to find the area:

Length: 2x + 1

Width: x + 4

A = l * w

A = (2x + 1)(x + 4)

2x^2 + 8x + x + 4

We can add like terms now:

2x^2 + 9x + 4

Our area is 2x^2 + 9x + 4

Our answer would be a(x)=2x^2+9x+4

7 0
3 years ago
Read 2 more answers
Is anybody else here to help me ??​
Akimi4 [234]

Answer:

\cot(x)+\cot(\frac{\pi}{2}-x)

\cot(x)+\tan(x)

\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}

\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]

\csc(x)[\frac{1}{\cos(x)}]

\csc(x)[\sec(x)]

\csc(x)[\csc(\frac{\pi}{2}-x)]

\csc(x)\csc(\frac{\pi}{2}-x)

Step-by-step explanation:

I'm going to use x instead of \theta because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

\cot(x)+\cot(\frac{\pi}{2}-x)

I'm going to use a cofunction identity for the 2nd term.

This is the identity: \tan(x)=\cot(\frac{\pi}{2}-x) I'm going to use there.

\cot(x)+\tan(x)

I'm going to rewrite this in terms of \sin(x) and \cos(x) because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: \frac{\cos(x)}{\sin(x)}=\cot(x) and \frac{\sin(x)}{\cos(x)}=\tan(x)

So we have:

\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}

I'm going to factor out \frac{1}{\sin(x)} because if I do that I will have the \csc(x) factor I see on the right by the reciprocal identity:

\csc(x)=\frac{1}{\sin(x)}

\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show \cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)} is equal to \csc(\frac{\pi}{2}-x).

So since I want one term I'm going to write as a single fraction first:

\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}

Find a common denominator which is \cos(x):

\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}

\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}

\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}

By  the Pythagorean Identity \cos^2(x)+\sin^2(x)=1 I can rewrite the top as 1:

\frac{1}{\cos(x)}

By the quotient identity \sec(x)=\frac{1}{\cos(x)}, I can rewrite this as:

\sec(x)

By the cofunction identity \sec(x)=\csc(x)=(\frac{\pi}{2}-x), we have the second factor of the right hand side:

\csc(\frac{\pi}{2}-x)

Let's just do it all together without all the words now:

\cot(x)+\cot(\frac{\pi}{2}-x)

\cot(x)+\tan(x)

\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}

\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]

\csc(x)[\frac{1}{\cos(x)}]

\csc(x)[\sec(x)]

\csc(x)[\csc(\frac{\pi}{2}-x)]

\csc(x)\csc(\frac{\pi}{2}-x)

7 0
3 years ago
Other questions:
  • If g(x) = 3x is graphed on a coordinate plane, what is the y-intercept of the graph? 0
    13·2 answers
  • Question 3 . amaths really need help. calculus. reply quicky thanks
    10·1 answer
  • Write the equation that would model problem number 26 of the Rhind Papyrus:
    9·2 answers
  • Is the algebra 1 regents hard?
    9·1 answer
  • Christian is cooking cookies the recipe calls for 6 cups of flour she accidentally put in a cups how many extra Cups did she put
    9·1 answer
  • PLEASE I'm DESPERATE!. Find a, b, c, and d such that the cubic . f(x) = ax3 + bx2 + cx + d. satisfies the given conditions.. Rel
    15·2 answers
  • Help im in the 6th grade
    14·2 answers
  • What is 2350 million in standard from
    5·1 answer
  • Two triangles are graphed below. Are the two triangles similar?
    8·1 answer
  • Find x<br><br> ………….. ………….. …………..
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!