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vazorg [7]
3 years ago
9

Graph the solution set to the inequality -s/2 + 5 < 4 Please help!!!

Mathematics
1 answer:
IceJOKER [234]3 years ago
5 0

Answer:

Draw a same side int. angle with s/2 as the perp. bisector

Step-by-step explanation:


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15.05

Step-by-step explanation:

Also, you don't need to add the zeros, they don't mean anything.

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the outdoor temperaturedeclines 3 degrees each hour for 5 hours. What is the change in temperature at the end of those 5 hours?
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15 degrees will be declined in the 5 hours.
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What is the solution to −1.2b−5.3≥1.9
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If you want me to solve for b then

b  ≤  − 6





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What is a relation and what makes it different from a function? How can you determine the domain and range of a function?
Misha Larkins [42]

Answer:

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3 years ago
The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

8 0
3 years ago
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