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Andrew [12]
2 years ago
8

The radius of a circle is (x-3)m. find the area of the circle

Mathematics
1 answer:
Flura [38]2 years ago
8 0

Answer:

πx² -6πx + 9π

or

π(x² - 6x + 9)

Step-by-step explanation:

area = πr² = π(x-3)² = π(x² - 6x + 9) = πx² - 6πx + 9π

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A rectangle's length is three times its width. Let w denote the rectangle's width. What polynomial represents the rectangle's ar
Ket [755]
<span>A = l x w
Since 
l = 3w

Substitute the l with 3w
The formula will be

A = 3w + w
A = 4w

An example:
The given known values are: Length of 4 cm Width is unknown Perimeter is 34 cm Find the dimensions of the rectangle.   Since the geometric formula for perimeter is: </span>
P= 2 (l + w) 
L = 2w – 4 cm 
W =?   
Derivation and solution: 
34 = 2 (2w - 4) + 2w <span>
34 =  4w – 8 + 2w</span> 
42 = 6w 42/6 = w 
W = 7 cm   

34 = 2l + 2(7) 
34 = 2l + 14 
2l = 34 – 14 
2l = 20 
L = 20/2 
L = 10 cm<span> <span>
</span></span>

7 0
2 years ago
Can anyone help me with this dont answer if you dont no what it is and no deleting answers
Mkey [24]
The answer to this question is the second choice, jessica bought 1/4 more than derek

6 0
1 year ago
the value of y varies directly proportional to the value of x. When x = 50, the value of y= 2500. What is the value of y, when x
USPshnik [31]

Answer:

The required value of y is 4800

4 0
3 years ago
What is the sum of 3.6 × 103 and 6.1 × 103?
ahrayia [7]
999.1 is the answer you multiply both then add
5 0
3 years ago
Read 2 more answers
4. Diego is thinking of two positive numbers. He says, "If we triple the first number and
aleksandr82 [10.1K]

Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

Now,  3<em>x </em>+ 2<em>y</em> = 34

3<em>x </em>= 34 - 2<em>y</em>

Let x = 10 and by substituting its value in above expression,

3 \times 10 = 34 - 2y

30 = 34 - 2y

2y = 34 - 30

2y = 4

y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

In the same way put x = 4 then,

3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

2y = 34 - 12

2y = 22

y = 11

Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)

Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

8 0
2 years ago
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