We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
Answer: 94
Step-by-step explanation: use photo math :)
Answer:
x=60
Step-by-step explanation:
Given that ,
HCF of 140 and x=20,
LCM of 140 and x =420.
Solution:
It is known that the product of two numbers is equal to the product of their HCF and LCM, i-e:
140*x= HCF*LCM
Putting in the values provided,
140*x=20*420
140*x=8400
x=8400/140
x=60
Hence the variable x is 60.
20 and 2
20 - 2 = 18
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The answer is D. 4x + 3y = -6
I first found the slope using the slope formula. Then I plugged in the values of the given coordinate and the slope I found into the point slope form equation, then I simplified. Then I manipulated the equation to get x and y on the right side, and the constant on the left side. Finally, I multiplied both sides by 3 to get rid of the fraction.