If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4
Hope this Helps! :)
Your answer is 1/4, -7/3,-4
Refer to the diagram shown below.
The shaded area satisfies the two inequalities
y > x - 1
and
y < 1 -x
Answer: A and D
x + 16 = 64 |subtract 16 from both sides
x = 48
The slope of the line can be defined as y = mx + b, where m is the slope
To find the slope, one will need to use the expression Δy/Δx (y final - y initial)/(x final - x initial)
For this problem, that equals 1/3
Now we will use the point slope form
(y - y initial) = m (x - x initial):
y + 1 = 1/3 (x - 2)
y = 1/3x - 5/3
