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galben [10]
3 years ago
9

The length of a rectangle is represented by (6x − 2), and the width is represented by (x − 1). Which expression best represents

the area of the rectangle?
Mathematics
2 answers:
Olenka [21]3 years ago
7 0
The are of a rectangle can be obtained by using the formula 

A=L*W

Since we are already given with the L, which is (6x-2), and the width, which is (x-1), the area of the rectangle is then

A = (6x-2)(x-1)

which, upon further simplification will give us

A = 6x^2-2x-6x+2

Combining like terms will yield

A = 6x^2-8x+2

Hence, the area of the specified rectangle is represented by the expression 6x^2 -8x +2.
saveliy_v [14]3 years ago
5 0

Answer:

The correct answer on Usatestprep is 14x-6

Step-by-step explanation:

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3 years ago
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
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