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galben [10]
3 years ago
9

The length of a rectangle is represented by (6x − 2), and the width is represented by (x − 1). Which expression best represents

the area of the rectangle?
Mathematics
2 answers:
Olenka [21]3 years ago
7 0
The are of a rectangle can be obtained by using the formula 

A=L*W

Since we are already given with the L, which is (6x-2), and the width, which is (x-1), the area of the rectangle is then

A = (6x-2)(x-1)

which, upon further simplification will give us

A = 6x^2-2x-6x+2

Combining like terms will yield

A = 6x^2-8x+2

Hence, the area of the specified rectangle is represented by the expression 6x^2 -8x +2.
saveliy_v [14]3 years ago
5 0

Answer:

The correct answer on Usatestprep is 14x-6

Step-by-step explanation:

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lina2011 [118]
12,000,000+400,000+30,000+
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3 years ago
What is 2logx−logy+2logz written as a single logarithm? log(xz)^2/y log2x/2yz logx^2y/z^2 logx^2/yz^2
Klio2033 [76]

Answer: \log\dfrac{x^2z^2}{y}

Step-by-step explanation:

Properties of logarithm:

(i)\ \ n\log a = a^n\\\\ (ii)\ \ \log m +\log n =\log (mn)\\\\ (iii)\ \ \log m-\log n =\log\dfrac{m}{n}

Consider,

2\log x-\log y+2 \log z\\\\ =\log x^2-\log y+\log z^2\ \ \ \ \text{[By (i)]}\\\\= \log x^2+\log z^2-\log y\\\\=\log(x^2z^2)-\log y\ \ \ \ [\text{By } (ii) ]\\\\=\log(\dfrac{x^2z^2}{y})    \ \ \ \ [\text{By (iii)}]

3 0
3 years ago
PLS HELP ITS MATH AND I DONT UNDERSTAND <br> No links pls and ty &lt;3
tankabanditka [31]
<h3>Answer:</h3>

C=52.08π

<h3>Solution:</h3>
  • Circumference of a circle:
  • C=2πr
  • where
  • π=3.14...
  • r= radius
  • In this case, r is equivalent to 26.04 ft.
  • C=2π×26.04
  • Multiply:
  • C=52.08π (in terms of pi)

Hope it helps.

Do comment if you have any query.

8 0
3 years ago
Read 2 more answers
Please help with math ​
RoseWind [281]
Break the problem up.
8 0
3 years ago
Need help! Show work
Sergeu [11.5K]
The first step for each of these is adding or subtracting the coefficient to isolate your terms with variables. And then divide to isolate the variable itself.
8 0
3 years ago
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