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LenKa [72]
3 years ago
8

A particular movie theater charges $ 9.00 per adult ticket and $ 3.5 0 per child ticket. Suppose 550 people attended a movie and

the total revenue from ticket sales was $ 3575 . Write two linear equations to represent a system to solve this, where x represents the number of adults attending the movie and y represents the number of children attending the movie. Write the equations, but do not solve them. The first equation must come from the information given about the total attendance and the second must come from the ticket prices and revenue. 1)= ? 2)= ?
Mathematics
2 answers:
irakobra [83]3 years ago
5 0

Answer:

Step-by-step explanation:

Number of children = y

Number of adults = x

Total people = 550

x + y = 550 ------------------ (I)

Charge for 'y' children =3.50 * y = 3.5y

Charge for 'x' adult = 9 * x = 9x

Total amount = $ 3575

9x  + 3.5y = 3575 -------------(II)

Multiply equation (I) by (-9)

(I)*(-9)  -9x - 9y = -4950  

(II)        <u> 9x  + 3.5y = 3575</u>  { Now add and so 'x' will be eliminated}

                  - 5.5y   =  -1375

y = -1375/-5.5

y = 250

Plug in y = 250 in equation (I)

x + 250 = 550

            x = 550 - 250

            x = 300

Number of children = 250

Number of adults = 300

Lunna [17]3 years ago
4 0

Answer:

If x represents the no. of adults

and y represents the children, then

x + y = 550

9x + 3.50y = 3575

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An individual saves $5000 in a bank account at the beginning of each year for 10 years.
frozen [14]

Answer:

a) Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually is $5849.5

Step-by-step explanation:

Principal Amount P = 5000

Time t = 10 years

Annual interest i = 8% = 0.08

We need to find amount saved if interest is compounded a) annually b) semi-annually

a) Amount saved if the interest is compounded annually

If interest compounded annually, n= 1

Using Formula: A=P(1+\frac{r}{n})^{nt}

Putting values:

A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{1})^{1*2}\\A=5000(1+0.08)^2\\A=5000(1.08)^2\\A=5000(1.1664)\\A=5832

So, Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually

If interest compounded semi-annually, n= 2

Using Formula: A=P(1+\frac{r}{n})^{nt}

Putting values:

A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{2})^{2*2}\\A=5000(1+0.04)^4\\A=5000(1.04)^4\\A=5000(1.1699)\\A=5849.5

So, Amount saved if the interest is compounded semi-annually is $5849.5

4 0
3 years ago
If a rectangle has a base of 6' and a height of 4' its area would be what?
zavuch27 [327]
24 sq.ft. Is the answer if not then I’m sorry
6 0
2 years ago
A boat traveled 27 miles in 2 hours. At this rate, how many miles will the boat travel in 12 hours?
ArbitrLikvidat [17]

Answer:

162 miles.

Step-by-step explanation:

You need to find the rate. 27/2=13.5 miles per hour as the rate

You multiply 13.5 x 12.

You get 162 miles as the answer.

6 0
3 years ago
Read 2 more answers
Harper has $15to spend at the grocery store.She is going to buy bags of fruit that cost $4.75 each and one box of crackers that
Yuki888 [10]

Answer:

The maximum number of fruits bag Harper can buy are 3.

Step-by-step explanation:

Let there be x bags of fruits.

Let there be y boxes of chocolates

Cost of 1 bag of fruit = $4.75

So, cost of x bags = $4.75x

Cost of one box of crackers costs = $3.50

As per the given situation, the inequality forms:

4.75x+3.50y\leq 15

So, the maximum number of bags of fruit Harper can buy, is when she buys no box of cracker.

So, putting y = 0 in above inequality , we have,

4.75x+3.50(0)\leq 15

=> 4.75x+0\leq 15

=> 4.75x \leq 15

x\leq 3.15 rounding to 3.

Hence, the maximum number of fruits bag Harper can buy are 3.

5 0
3 years ago
A certain portfolio consisted of 5 stocks, priced at $20, $35, $40, $45, and $70, respectively. On a given day, the price of one
saveliy_v [14]

Answer:

Option E: 35, 40, 45

Step-by-step explanation:

To solve this problem we can test the options, checking if the calculations will match the result.

A.

20, 35 and 70 remained constant.

The average price of a stoc in the portfolio before the changings were:

(20+35+40+45+70)/5 = 42

With an increase of approximately 2%, the average value will be approximately 42*1.02 = 42.84

If the average price of a stock in the portfolio rose, and the rise of one stock in percentage was bigger than the fall of the other stock, we need to choose the stock that has the bigger price as the one that increased its value.

An increase of 15% is calculated multiplying the base value by 1.15, and a decrease of 35% is calculated multiplying the base value by (1-0.35)=0.65.

So, if the stocks affected were the $40 and 45$, we have that:

(20+35+40*0.65+45*1.15+70)/5 = 40.55

That's not the correct answer.

B.

20, 45 and 70 remained constant.

Affected: 35 and 40

(20+35*0.65+40+45*1.15+70)/5 = 40.9

That's not the correct answer.

C.

20, 35 and 40 remained constant.

Affected: 45 and 70

(20+35+40+45*0.65+70*1.15)/5 = 40.95

That's not the correct answer.

D.

35, 40 and 70 remained constant.

Affected: 20 and 45

(20*0.65+35+40+45*1.15+70)/5 = 41.95

That's not the correct answer.

E.

35, 40 and 45 remained constant.

Affected: 20 and 70

(20*0.65+35+40+45+70*1.15)/5 = 42.7

That's the correct answer, with an increase in the average value of 0.7/42 = 0.0167 = 1.67%

6 0
3 years ago
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