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LenKa [72]
3 years ago
8

A particular movie theater charges $ 9.00 per adult ticket and $ 3.5 0 per child ticket. Suppose 550 people attended a movie and

the total revenue from ticket sales was $ 3575 . Write two linear equations to represent a system to solve this, where x represents the number of adults attending the movie and y represents the number of children attending the movie. Write the equations, but do not solve them. The first equation must come from the information given about the total attendance and the second must come from the ticket prices and revenue. 1)= ? 2)= ?
Mathematics
2 answers:
irakobra [83]3 years ago
5 0

Answer:

Step-by-step explanation:

Number of children = y

Number of adults = x

Total people = 550

x + y = 550 ------------------ (I)

Charge for 'y' children =3.50 * y = 3.5y

Charge for 'x' adult = 9 * x = 9x

Total amount = $ 3575

9x  + 3.5y = 3575 -------------(II)

Multiply equation (I) by (-9)

(I)*(-9)  -9x - 9y = -4950  

(II)        <u> 9x  + 3.5y = 3575</u>  { Now add and so 'x' will be eliminated}

                  - 5.5y   =  -1375

y = -1375/-5.5

y = 250

Plug in y = 250 in equation (I)

x + 250 = 550

            x = 550 - 250

            x = 300

Number of children = 250

Number of adults = 300

Lunna [17]3 years ago
4 0

Answer:

If x represents the no. of adults

and y represents the children, then

x + y = 550

9x + 3.50y = 3575

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Soft drink consumption in New Zealand. A survey commissioned by the Southern Cross Healthcare Group reported that 16% of New Zea
lidiya [134]
<h2>Answer with explanation:</h2>

Given : The proportion of New Zealanders consume five or more servings of soft drinks per week :\hat{p}= 0.16

a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006

b) Confidence interval for population proportion (p) :

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} = Sample proportion.

n= Sample size.

z* = Critical value.

For n= 2006 , \hat{p}= 0.16 and critical value for 95% confidence interval : z* = 1.96

Then , the required confidence interval will be :

0.16\pm (1.96)\sqrt{\dfrac{ 0.16(1- 0.16)}{2006}}

0.16\pm (1.96)\sqrt{ 0.000066999002991}

0.16\pm (1.96)(0.00818529186963)

0.16\pm 0.0160431720645

(0.16-0.0160431720645,\ 0.16+0.0160431720645)

(0.143956827935,\ 0.176043172064)\approx(0.144,\ 0.176)

i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = (0.144,\ 0.176)

c) (0.144,\ 0.176)=(0.144\times100\%,\ 0.176\times100\%)

=(14.4\%,\ 17.6\%)176\times100\%)[/tex]

d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.

6 0
3 years ago
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