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valina [46]
3 years ago
15

Every year after a new car is

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

Answer: The value of the car after 3 years is $5,333.333

And no, the relationship is not linear, is an exponential decay.

Step-by-step explanation:

We know that every year, the car loses 1/3 of its value.

So if the initial value of the car is V.

After one year, the new value of the car will be:

Value (1 year) = V - (1/3)*V = (2/3)*V

After another year, the value will be:

Value (2 years) = (2/3)*V - (1/3)*(2/3)*V = V*(2/3)^2

Ok, we already can see that this is an exponential decay.

(So no, this is not a linear relationship).

The value equation as a function of the number of years will be:

Value(N) = V*(2/3)^N

Then if the initial cost of a car is $18,000, and we want to know its value after 3 years, we need to replace V by $18,000 and N by 3 in the above equation:

Value(3) = $18,000*(2/3)^3 = $5,333.333

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EastWind [94]
It takes 6 seconds for it to hit the ground.

0 = -5x²+20x+60

We can solve this by factoring.  First factor out the GCF, -5:

0 = -5(x²-4x-12)

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0 = -5(x-6)(x+2)

Using the zero product property, we know that either x-6=0 or x+2=0; this gives us the answers x=6 or x=-2.  Since we cannot have negative time, x=6.
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3 years ago
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What is the completely factored from of 9x2+24x+16
dezoksy [38]

Answer:

(3x+4)(3x+4) is factor of given expression.

B is correct.

Step-by-step explanation:

We are given an expression 9x^2+24x+16

Formula: a^2+2ab+b^2=(a+b)^2

First we write each term as perfect square as formula.

\Rightarrow 9x^2+24x+16

\Rightarrow (3x)^2+2\cdot 3x\cdot 4+4^2

Using formula , a=3x and b=4

\therefore (3x)^2+2\cdot 3x\cdot 4+4^2=(3x+4)^2

Now we write same number two times.

Hence, (3x+4)(3x+4) is factor of given expression.

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2 years ago
Hozumi recorded the daily high temperatures for an 18-day period in the table shown please I need this really badly
mr Goodwill [35]

Answer:

the answer is letter A

Step-by-step explanation:

7 0
3 years ago
What is the quotient of 2 1/9÷3 4/5
Karolina [17]

Answer:

\frac{5}{9}

Step-by-step explanation:

2 \frac{1}{9}  \div 3 \frac{4}{5}  \\  \\  =  \frac{2 \times 9 + 1}{9}  \div  \frac{3 \times 5 + 4}{5}  \\  \\  =  \frac{18 + 1}{9}  \div  \frac{15 + 4}{5}\\  \\  =  \frac{19}{9}  \div  \frac{19}{5}\\  \\  =  \frac{19}{9}  \times  \frac{5}{19} \\  \\  =  \frac{5}{9}

4 0
3 years ago
A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali
Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

W = Wednesday

T = Thursday

F = Friday

S = Saturday

Their corresponding probabilities are

P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1

Since Y = number of days beyond Wednesday that it takes for both magazines to arrive(so possible Y values are 0, 1, 2 or 3)

The possible number of outcomes are therefore 4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)

The values associated for each of the outcomes are as follows:

Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3

The probability mass function of Y is,

P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19

7 0
3 years ago
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