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3 years ago

You toss a coin and roll a number cube. Find P(heads and an even number)

2 answers:

3 0

"and" means summe
P(coin)+P(cube)=1/2+1/6=0,666667
The chance to get head is always 1/2 no matter how often you toss the coin
And the chance to get a number when you roll a number cube is always 1/6

Did you mean that?

ivanzaharov [21]3 years ago

3 0

<span>there are 12 possible outcomes.
Heads - 1
Heads - 2
Heads - 3
Heads - 4
Heads - 5
Heads - 6
Tails - 1
Tails - 2
Tails - 3
Tails - 4
Tails - 5
Tails - 6

You want heads AND an even number, so that narrows it down to three.
Heads - 2
Heads - 4
Heads - 6

So thats 3/12 chance, which is simply a 25.00 percent chance.

Much simper way to do so is that are 4 outcomes if you don't count the numbers.
Heads - Even
Heads - Odd
Tails - Even
Tails - Odd

so you can also get 25.0% that way.</span>

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Sean said that the slope of the line is 3. is he correct?

krok68 [10]

Answer:

yes

Step-by-step explanation:

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3 years ago

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Merchandise is ordered on November 10; the merchandise is shipped by the seller and the invoice is prepared, dated, and mailed b

natali 33 [55]

Answer:

November 13

Step-by-step explanation:

Following dates are given

On November 10 = Merchandise ordered

Date of an invoice prepared, dated and mailed = November 13

Date when the merchandised received by the buyer = November 18

So, the credit period begins when the invoice is prepared, dated and the mailed by the seller to the buyer as it is the evidence of that the merchandise is ordered

4 0

3 years ago

Amuseumcharges forgeneraladmission and exhibitions. Admission and 3 exhibitionscosts $45. Admission and 5 exhibitionscosts $65.

leonid [27]

Answer:

The price of the admission is 15.

Step-by-step explanation:

From the information given, you can write the following equations:

a+3e=45 (1)

a+5e=65 (2), where:

a is the admission cost

e is the exhibition cost

First, you can solve for a in (1):

a=45-3e (3)

Second, you can replace (3) in (2):

45-3e+5e=65

45+2e=65

2e=65-45

2e=20

e=20/2

e=10

Finally, you can replace the value of e in (3):

a=45-3e

a=45-3(10)

a=45-30

a=15

According to this, the price of the admission is 15.

3 0

3 years ago

What is the probability that a two-digit number selected at random has a tens digit less than its units digit

Reika [66]

The probability that a two-digit number selected at random has a tens digit less than its units digit is 0.2667 (4/15).

$A=24B=90\\\\P=A/B\\\\P=24/90\\p=4/15$

There are 90 two-digit numbers (99-9). Of these, six numbers are divisible by 15 (15, 30, 45, 60, 75, 90). This is also divisible by 5. Therefore, the preferred case is 30-6 = 24. Therefore, the required probability is 24/90 = 4/15.

The probability of an event can be calculated by simply dividing the number of favorable results by the total number of possible results using a probabilistic expression. Whenever you are uncertain about the outcome of an event, you can talk about the probability of a particular outcome, that is, its potential.

Learn more about probability here: brainly.com/question/24756209

#SPJ4

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2 years ago

you and four of your nine classmates received an A on your math test, what is the simplest fraction of students that scored an A

svetlana [45]

4/9 or four/ninths. it cant simplify.

7 0

3 years ago

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