Answer:
The answer to your question is letter D
Step-by-step explanation:
Formula
m∠E = ![\frac{1}{2} ( DGF - DF)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%28%20DGF%20-%20DF%29)
Data
m∠E = 48°
DGF = 228°
DF = x°
Substitution
48° = ![\frac{1}{2} ( 228° - x°)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%28%20228%C2%B0%20-%20x%C2%B0%29)
Solution
2(48) = 228 - x°
96 = 228 - x°
96 - 228 = - x°
- 132 = - x°
x° = 132°
2/3(6c+4)-(8c-5)
1) Get rid of the negative signs
New equation (the ones in bold are the changes): 2/3(6c+4)+(-8c)+(5)
2) Use distributive property for the first part by multiplying 2/3*6c= 4c and 2/3*4= 2 2/3
New equation: 4c+2 2/3+ (-8c) + 5
3) Combine like terms: 4c+(-8c)= -4c and 2 2/3+5= 7 2/3
New and simplified equation: -4c+ 7 2/3
parallel lines have the same slope
y = 4x-5 the slope is 4
slope intercept form
y= mx+b
the slope is 4 and the y intercept is 3
y = 4x +3
Answer:
A. (1.55, 2)
Step-by-step explanation:
The formula to apply when finding the midpoint of a segment where the coordinates of the end points are given is;
![midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )](https://tex.z-dn.net/?f=midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%20%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%20%29)
where (x₁,y₁) and (x₂,y₂) are the coordinates of the end points
Given;
x₁= -0.4 ,y₁=2.5, x₂=3.5, y₂=1.5 then applying the formula for midpoint
![=(\frac{-0.4+3.5}{2} ,\frac{2.5+1.5}{2} )\\\\\\=(\frac{3.1}{2} ,\frac{4.0}{2} )\\\\\\=(1.55,2.0)](https://tex.z-dn.net/?f=%3D%28%5Cfrac%7B-0.4%2B3.5%7D%7B2%7D%20%2C%5Cfrac%7B2.5%2B1.5%7D%7B2%7D%20%29%5C%5C%5C%5C%5C%5C%3D%28%5Cfrac%7B3.1%7D%7B2%7D%20%2C%5Cfrac%7B4.0%7D%7B2%7D%20%29%5C%5C%5C%5C%5C%5C%3D%281.55%2C2.0%29)
Surface area of the the rectangles:
8 * 5 + 8 * 4 + 8 * 3 = 96
Surface area of the two triangles:
Use bh/2 base time height over 2
(4 * 3)/2 = 6
There are 2 triangles, 2 * 6 = 12
12 + 96 = 108