The answer is False!
P - dominant allele for inflated pods
p - recessive allele for inflated pods
PP - homozygote with inflated pods
Pp - heterozygote with inflated pods
pp - homozygote with inflated pods
S - dominant allele for round seeds
s - recessive allele for wrinkled seeds
SS - homozygote with round seeds
Ss - heterozygote with round seeds
ss - homozygote with wrinkled seeds
1. <span>A Pea plant that is homozygous for inflated pods are heterozygous for round seeds: PPSs
2. A</span><span> plant that is heterozygous for inflated pods and a homozygous for wrinkled seeds: Ppss
Let's look at their genotypes separately, and cross them that way:
Parents: PP x Pp
Offspring: PP PP Pp Pp
All of the offspring will have the same phenotype (100% = 1). So, this trait does not affect phenotypic ratio
</span>Parents: Ss x ss
Offspring: Ss Ss ss ss
Half of the offspring will have wrinkled seeds and half of them will have round seeds: 50% : 50% = 1 : 1
So, the phenotypic ratio is not 1 : 3
60 centimeters (2 ft 0 in) to over 260 cm( 8 ft 6 in)
1. Suzie's hypothesis (i.e. prediction of results) is that ferns which are placed in white light will grow to a taller height after two weeks than ferns which are placed in other coloured light or in a closet.
2. Her independent variable (the thing she changes to produce a result) is the kind of light that she places each plant in.
3. The dependent variable (the thing she measures) is the height of the plants after two weeks.
4. I would say her control group would be the plant placed in the closet, because every other group is exposed to some form of light.
5. I would say that Suzie has 4 experimental groups: white, red, blue, and green light.
6. The constant variables were the amount of water each plant was given, the initial height of the plants, the age of the plants, the species of fern, and what she planted the ferns in.
7. To determine how each fern did, Suzie could measure the height in addition to noting the appearance of all the plants. E.g. did any look paler than the others?