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Natasha2012 [34]
3 years ago
7

50 = 5G + 2 – G What is this answer

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

g=12

Step-by-step explanation:

50=5g+2-g  

One solution was found :

                  g = 12

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    50-(5*g+2-g)=0  

Step by step solution :

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  48 - 4g  =   -4 • (g - 12)  

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    -4   =  0

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    g-12 = 0  

Add  12  to both sides of the equation :  

                     g = 12

One solution was found :

                  g = 12

Artemon [7]3 years ago
5 0
50=5G+2-G
50=4G+2
-2. -2
———————-
48=4G
— —-
4. 4

G=12
————-

I don’t know if this is Right but uk
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The perimeter of a rectangle is 128 inches.
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Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.

<h3>What is the perimeter of a rectangle?</h3>

The perimeter of a rectangle of length l and width w is given as follows:

P = 2(l + w).

The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:

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More can be learned about the perimeter of a rectangle at brainly.com/question/10489198

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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
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Answer:

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Step-by-step explanation:

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In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

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Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

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