(1+x^2)^8
=(1+8x^2+8*7/(1*2)x^4+8*7*6/(1*2*3)x^6+8*7*6*5/(1*2*3*4)x^8+....)
=1+8x^2+28x^4+56x^6+70x^8+....)
For x<1, higher power terms diminish in value, hence we can approximate powers of numbers.
1.01=(1+0.1^2) => x=0.1 in the above expansion
(1.01)^8
=1+8(0.1^2)+28(0.1^4)+56(0.1^6) [ limited to four terms, as requested]
=1+0.08+0.0028+0.000056 (+0.00000070)
=1.082856 (approximately)
Question :
5m^2 - 29m + 20
Steps:
What can u factor to get 20?
you can make 5 and 4 to make 20 so,..
1. Break it into groups
(5m^2 - 4m) + (-25m + 20)
*Factor out m from (5m^2 - 4m) : m(5m - 4)
*Factor out -5 from (-25m + 20) : -5(5m - 4)
2. Then, you can factor out the common term : (5m - 4) because they both have it. And then u would move the m by the -5 so,...
= (5m - 4)(m - 5) <======= <em>Answer</em>
Hope this helped!!!
~Shane
Answer:
1) Yes 2)No
Step-by-step explanation:
1) Yes because the two shorter lines combined are longer than the base and so those two lines are able to make a triangle.
2) No because the two lines on top will be equal to base line and so the two shorter lines will not be able to make a third angle because it will be level with the base.
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
