I'm so lost with this math problem

Describe using words in a sentence the transformations that must be applied to the graph of f to obtain thegraph of g(x) = -2 f(

grin007 [14]

we have

f(x)

and

g(x)=-2f(x)+5

so

step 1

First transformation

Reflection about the x-axis

so

f(x) -----> -f(x)

step 2

Second transformation

A vertical dilation with a scale factor of 2

so

-f(x) ------> -2f(x)

step 3

Third transformation

A translation of 5 units up

so

-2f(x) -------> -2f(x)+5

5 0

1 year ago

You are given the system of equations to solve by the elimination method, which is an INCORRECT step that will NOT produce a

SCORPION-xisa [38]

Answer: multiply x by 2 in the first equation and subtract the second equation

Step-by-step explanation:

To solve a system of linear equations by elimination method , our first step is to make its (either x or y) coefficient same.

For that we multiply a number to both sides of the equation not to only one term.

So by checking all the given options it is pretty clear that the last option is not applicable for elimination method because in this 2 is multiplied to only one term, which proceeds to loose the balance of the equation.

Thus , an INCORRECT step that will NOT produce a system with the same solution is "multiply x by 2 in the first equation and subtract the second equation ".

6 0

3 years ago

Help please i want help please

Rasek [7]

Don't listen but i'm gonna go with the third one

3 0

3 years ago

PLEASE HELP ME UNDERSTAND! I don’t know how to find.... ML , CD, AC, UW (one explanation is ok too)

nlexa [21]

Step-by-step explanation:

So the way you do this is if it says 'Find AC' and on the angle you see different letters connect then on the lines and name the angle

More that 90°= Obtuse

90° angle= 90° angle

Less than a 90° angle= isosolines angle

4 0

2 years ago

The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.

devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z $\leq 1.72$ ). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15) from 1. Therefore, we have 1- P(Z $\leq -1.09$ ). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z $\leq 1.72$ ). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15) from 1. Therefore, we have 1- P(Z $\leq -1.09$ ). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0

3 years ago