Question

If h = 12 units and r = 4 units, what is the volume of the cone

Answer 1

$V= \pi r^2 \frac{h}{3} \\ V= \pi 4^2 \frac{12}{3} \\ V= 16*4\pi \\ V=64\pi$
The volume is 64 pi. If you substitute 3.14 for pi, you get 200.96.

Answer 2

The volume would be 201.06