The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
Answer:
0.16625
Step-by-step explanation:
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Answer:
y-intercepts: (-3,0) , (-1,0) , (1,0)
Step-by-step explanation:
Answer:
first term: 7
find the 17th term : 102
fifteent term: 10
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
