Its okay bro, we all failed
First you have to factor the equation because there are technically 2 x’s in an x^2. You will get x(x+6)=0 because x*x=x^2 and 6*x=6x. Now you can come up with possible values. If you make the first x, 0, you are multiplying everything by 0 and will get the product of 0. So, one of the and coordinates is x=0. You can also substitute -6 for the second x in the equation so that in the parentheses it would be x(-6+6)=0. You’re basically multiplying 0 by x which will guarantee you to get 0. So, the answer is (0,-6). If you have any questions feel free to comment.
X = y - 3
x + 3y = 13
x + 3y = 13 (replace x with y-3)
y - 3 + 3y = 13
4y - 3 = 13
4y = 13 + 3
4y = 16
y = 16/4
y = 4
x = y - 3
x = 4 - 3
x = 1
The answer is A. (1,4)
the answer for this question 25/16
