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Nady [450]
3 years ago
14

Is 0.5 less than 0.25

Mathematics
2 answers:
olga55 [171]3 years ago
5 0
No 0.5 is greater than 0.25
Andrews [41]3 years ago
4 0
No,

0.5=0.50 >0.25
......................
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The mean salary of 5 employees is $33700. The median is $34600. The mode is $35600. If the median paid employee gets a $3500 rai
fgiga [73]

Step-by-step explanation:

Given:

Mean = 33700

Median = 34600

Mode = 35600

The mean is the average, the median is the middle number, and the mode is the most common number.

a)

First, we need to find the new mean (average) if one of the employees gets a 3500 raise.  The average is the total salary divided by number of employees:

(5 × 33700 + 3500) / 5 = 34400

b)

The mode is the most common number in a set.  Since there are only five employees, and the mode is different than the median, then the two highest earners must have the same salary.  The salaries from smallest to largest is therefore:

?, ?, 34600, 35600, 35600

When the median gets the 3500 raise, the set becomes:

?, ?, 35600, 35600, 38100

So the new median is 35600.

c)

The most common number is still 35600.  So the mode hasn't changed: 35600.

4 0
3 years ago
How do u do long division
Archy [21]

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8 0
3 years ago
Solve <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x-10%7D%7B4%7D" id="TexFormula1" title="\frac{2x-10}{4}" alt="\frac{2x-10}{4}
GREYUIT [131]
X = -1!
1. Factor out 2 from the expression : 2(x-5) / 4 = 3x
2. Reduce the fraction with 2 : x-5 / 2 = 3x
3. Multiply both sides of the equation by 2 : x-5=6x
4. Move the terms : x - 6x = 5
5. Collect like terms : -5x = 5
6. Divid both sides by -5
Hope this helps!
8 0
3 years ago
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frutty [35]
1. Is 8 seconds
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7 0
3 years ago
Read 2 more answers
An insurance company divides its policyholders into low-risk and high-risk classes. 60% were in the low-risk class and 40% in th
AleksAgata [21]

Answer:

a). 0.294

b) 0.11

Step-by-step explanation:

From the given information:

the probability of the low risk = 0.60

the probability of the high risk = 0.40

let C_o represent no claim

let C_1 represent 1 claim

let C_2 represent 2 claim :

For low risk;

so, C_o  = (0.80 * 0.60 = 0.48),  C_1 =  (0.15* 0.60=0.09),   C_2 = (0.05 *  0.60=0.03)

For high risk:

C_o  = (0.50 *  0.40 = 0.2),  C_1 =  (0.30 *  0.40 = 0.12) ,   C_2 = ( 0.20 *  0.40 = 0.08)

Therefore:

a),  the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:

P(H|C_o) = \dfrac{P(H \cap C_o)}{P(C_o)}

P(H|C_o) = \dfrac{(0.2)}{(0.48+0.2)}

P(H|C_o) = \dfrac{(0.2)}{(0.68)}

P(H|C_o) = 0.294

b) What is the probability that a randomly selected policyholder filed two claims?

the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08

= 0.11

7 0
3 years ago
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