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garri49 [273]
3 years ago
7

The square ABCD is divided into eight equal parts. The shaded area is 25 cm². What is the area of the square ABCD​

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

I think the answer is 200cm^2

Step-by-step explanation:

since the square is divided into eight equal parts

and one shaded part is =25cm^2

multiply the area of the shaded part by the number of equal parts

= 25cm^2 ×8

= 200cm^2

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For the linear equation, find the product of 5 and the linear equation, and solve both equations for y. 2x + 7y = 11
tensa zangetsu [6.8K]

Answer:

(a) 10x + 35y = 55

(b) y = \frac{11 - 2x}{7}

Step-by-step explanation:

Given

2x + 7y = 11

Solving (a): Multiply equation by 5.

Multiply both sides by 5

5 * (2x + 7y) = 11*5

Open bracket

5 * 2x + 5 * 7y = 11*5

10x + 35y = 55

(b) Solve for y in 10x + 35y = 55 and 2x + 7y = 11

10x + 35y = 55

Subtract 10x from both sides

35y = 55 - 10x

Divide both sides by 35

\frac{35y}{35} = \frac{55 - 10x}{35}

y = \frac{55 - 10x}{35}

Factorize the numerator:

y = \frac{5(11 - 2x)}{35}

Express 35 as 7 * 5

y = \frac{5(11 - 2x)}{7 * 5}

y = \frac{(11 - 2x)}{7}

y = \frac{11 - 2x}{7}

<em>When </em>2x + 7y = 11<em> is solved, the solution will be: </em>y = \frac{11 - 2x}{7}<em></em>

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3 years ago
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kramer

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If the probability of being hospitalized during a year is 0.15 find the probability that no one in the family of 4 will be hospi
Goryan [66]

The probability that no one in the family of 4 will be hospitalized during a year is 0.52

Step-by-step explanation:

The probability for a person to be hospitalized during one year is

p(h)=0.15

As a consequence, the probability for a person of NOT being hospitalized during one year is

p(h^{-1})=1-0.15=0.85

If we have 4 people in the family, the probability of each of them of NOT being hospitalized during the year is independent from the probability of the others - therefore, these are independent events. This means that the total probability of the 4 people of not being hospitalized during a year is:

p(h^{-1})^4=(0.85)^4=0.52

So, the probability that no one in the family of 4 will be hospitalized during a year is 0.52.

Learn more about probability:

brainly.com/question/5751004

brainly.com/question/6649771

brainly.com/question/8799684

brainly.com/question/7888686

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