Answer:
Solution : (15, - 11)
Step-by-step explanation:
We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )
Row Echelon Form :

Step # 1 : Swap the first and second matrix rows,

Step # 2 : Cancel leading coefficient in row 2 through
,

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

As you can see our solution is x = 15, y = - 11 or (15, - 11).
Subtract 4 from both sides
y−4≤−2x
Divide both sides by −2
- y-4/2 ≥ x
Switch sides
<span>x ≤ − y−4/2<span><span><span><span><span></span></span></span>
HOPE THIS HELPS!!
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(y^2-y-12)/(y^2-2y-15) factor both the numerator and denominator...
(y^2-4y+3y-12)/(y^2-5y+3y-15)
(y(y-4)+3(y-4))/(y(y-5)+3(y-5))
((y-4)(y+3))/((y-5)(y+3)) so the (y+3) terms cancel leaving
(y-4)/(y-5)
To find the population after t number of years, multiply the starting population by 1 plus the percent increase raised to the number of years.
The equation would be: P = 508(1.062)^t
Answer: 22x−2
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