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4 years ago

What expression is equivalent to b+b+b+b

Mathematics

2 answers:

Brums [2.3K]4 years ago

5 0

4b is equivalent to b+b+b+b

Alisiya [41]4 years ago

5 0

Answer:

Step-by-step explanation:

Since there are 4 bs then you put them all together and get 4b.

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Plsss help !!

Gennadij [26K]

Answer:

carnation $2.50; rose $3.00

Step-by-step explanation:

Let c = price of 1 carnation.

Let r = price of 1 rose.

3c + 5r = 22.5

3c + 2r = 13.50

Subtract the se3cond equation from the first equation.

3r = 9

r = 3

Now substitute r = 3 in the first equation and solve for c.

3c + 5r = 22.5

3c + 5(3) = 22.5

3c = 7.5

c = 2.5

Answer: carnation $2.50; rose $3.00

5 0

3 years ago

Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16).

Amanda [17]

Since you subtract 16 from the y value, P is (-2, 6), and the y value comes second (meaning that it's 6), we get 6-16=-10

4 0

3 years ago

Read 2 more answers

a mechanic buys $14.56 worth of parts from a supplier. if he pays for the parts with a $20 bill, how much change will he receive

Bond [772]

He will receive $5.04

3 0

3 years ago

Read 2 more answers

Is the function even,odd or neither and how do you know? ASAP

wlad13 [49]

Answer:

Odd

Step-by-step explanation:

6 0

3 years ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

3 years ago