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kykrilka [37]
4 years ago
6

What expression is equivalent to b+b+b+b

Mathematics
2 answers:
Brums [2.3K]4 years ago
5 0

4b is equivalent to b+b+b+b

Alisiya [41]4 years ago
5 0

Answer:

4b

Step-by-step explanation:

Since there are 4 bs then you put them all together and get 4b.

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Plsss help !!
Gennadij [26K]

Answer:

carnation $2.50; rose $3.00

Step-by-step explanation:

Let c = price of 1 carnation.

Let r = price of 1 rose.

3c + 5r = 22.5

3c + 2r = 13.50

Subtract the se3cond equation from the first equation.

3r = 9

r = 3

Now substitute r = 3 in the first equation and solve for c.

3c + 5r = 22.5

3c + 5(3) = 22.5

3c = 7.5

c = 2.5

Answer: carnation $2.50; rose $3.00

5 0
3 years ago
Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16).
Amanda [17]
Since you subtract 16 from the y value, P is (-2, 6), and the y value comes second (meaning that it's 6), we get 6-16=-10
4 0
3 years ago
Read 2 more answers
a mechanic buys $14.56 worth of parts from a supplier. if he pays for the parts with a $20 bill, how much change will he receive
Bond [772]
He will receive $5.04
3 0
3 years ago
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Is the function even,odd or neither and how do you know?<br><br> ASAP
wlad13 [49]

Answer:

Odd

Step-by-step explanation:

6 0
3 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
3 years ago
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