E) 2
Remember that the first derivative of a function is the slope of the function at any specified point. We've been told that f(0) = -5 and that f'(x) is always less than or equal to 3. So let's look at the available options and see what the average slope would have to be in order to get the specified value of f(2).
A) -10: (-10 - -5)/(2 - 0) = -5/2 = -2.5
B) -5: (-5 - -5)/(2 - 0) = 0/2 = 0
C) 0: (0 - -5)/(2 - 0) = 5/2 = 2.5
D) 1: (1 - -5)/(2 - 0) = 6/2 = 3
E) 2: (2 - -5)/(2 - 0) = 7/2 = 3.5
Now taking into consideration the mean value theorem, the value of the function f'(x) has to have the value equal to the average slope between the two points at at least one point between the two given values. For options A, B, C, and D it's possible for f'(x) to return values that make that slope possible. However, for option E, the mean value theorem indicates that f'(x) has to have the value of 3.5 for at least 1 point between x=0 and x=2. And since we've been told that f'(x) is less than or equal to 3 for all possible values of x, that is in conflict and f(2) can not have the value of 2.
Answer:
x = 1 is not part of the domain
Step-by-step explanation:
The denominator of g(x) cannot be zero as this would make g(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.
solve
x - 1 = 0 ⇒ x = 1 ← restricted value
Answer:
3^-9
Step-by-step explanation:
3^-4 • 3^-5
We know that a^b * a^c = a^(b+c)
3^-4 • 3^-5 = 3^(-4-5) = 3^ -9
Answer:
- Exponential growth.
Step-by-step explanation:
Given that: 
To rewrite the model in the form 
or 
![y=2(10)^{\frac{t}{12} }\\=2[(10)^\frac{1}{12}]^{t}\\=2[1.2115]^t\\](https://tex.z-dn.net/?f=y%3D2%2810%29%5E%7B%5Cfrac%7Bt%7D%7B12%7D%20%7D%5C%5C%3D2%5B%2810%29%5E%5Cfrac%7B1%7D%7B12%7D%5D%5E%7Bt%7D%5C%5C%3D2%5B1.2115%5D%5Et%5C%5C)
is in the form or where r=0.2115.
Since 1.2115>1, the model represents an exponential growth.
Answer:
no answer b/c the terms are unlike term
