To find the length of the ladder, you need to do Pythagorean theorem.
50^2 + 30^2 = x^2
2500 + 900 = x^2
x^2 =3400
x= square root of 3400
58.31 OR 10 root34
To find the angle:
tan theta = opposite/adjacent
50/30 = 5/3
theta = tan inverse of 5/3
= 59.04
Answer:
y=(5/2)x+14
Use the slope formula and slope-intercept form y=mx+b to find the equation
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Answer:
B) To represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Step-by-step explanation:
Here the point A is given as 3 on number line.
Point B is given as -5 on number line.
To find : IA-BI
The distance between any two point A and B is given as IA-BI.
Now, to find the absolute value:
IA-BI = I (3) - (-5)I
or, IA-BI = I (3) + 5I = I8I
= 8 units
or, IA-BI = 8 units
Hence, on the number line, the distance between -5 and 3 is 8 units.
And, to represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
We have the equations:
x + 3 = 15 and 3y - 1 = 2x - 4
x + 3 = 15 |-3
x = 12
Put the value of x to the second equation:
3y - 1 = 2(12) - 4
3y - 1 = 24 - 4
3y - 1 = 20 |+1
3y = 21 |:3
y = 7
<h3>Answer: x = 12 and y = 7.</h3>
