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1 year ago

Find the mean for the set of data. 0.2, 0.21, 0.17, 3.22, 0.2

Mathematics

2 answers:

Sholpan [36]1 year ago

7 0

Answer:

0.8

Step-by-step explanation:

Find the mean of the list:

(0.2, 0.21, 0.17, 3.22, 0.2)

The mean of a list of numbers is given by:

(sum of elements)/(number of elements)

(sum of elements) = 0.2 + 0.21 + 0.17 + 3.22 + 0.2:

(0.2 + 0.21 + 0.17 + 3.22 + 0.2)/(number of elements)

Counting, we see that the list has 5 elements:

(0.2 + 0.21 + 0.17 + 3.22 + 0.2)/5

0.2 + 0.21 + 0.17 + 3.22 + 0.2 = 4:

4/5

4/5 = 0.8:

Answer: 0.8

Maksim231197 [3]1 year ago

6 0

Answer:

0.8

Step-by-step explanation:

The mean of the data set can be found by adding all terms together and dividing by the amount of terms there is. In this case, add all the numbers and divide by 5:

(0.2 + 0.21 + 0.17 + 3.22 + 0.2)/5 =

(4)/5 = 0.8

0.8 is the mean for the given set.

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Answer:

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Step-by-step explanation:

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Knowing that $t_{0.99,15} = 2.602$ :

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Note that $102.8 \in [71.384 ; 126.416]$ so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.

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Point Q is the center of dilation. Line segment L M is dilated to created line segment L prime M prime. The length of L Q is 4 a

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Answer:

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Step-by-step explanation:

Given:

Q is the center of dilation

Pre-image (original image) = segment LM

New image = segment L'M'

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The length of QM = 3

The length of LL' = 4

The original image was dilated with scale factor = 2

QM' = ?

To determine segment QM', first we would draw the diagram obtained from the given information.

Find attached the diagram

When a figure is dilated, we would have similar shape in thus cars similar triangles.

Segment L'M' = scale factor × length of LM

Let LM = x

L'M' = 2x

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