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german
4 years ago
6

The town swimming pool is d feet deep. The width of the pool is 5 feet greater than 5 times its depth. The length of the pool is

50 feet greater than 5 times its depth. Enter a simplified expression to represent the volume of the pool.
Mathematics
1 answer:
Likurg_2 [28]4 years ago
5 0

Answer:

V = 25d ^ 3 + 275d ^ 2 + 250d

Step-by-step explanation:

If the pool has a rectangular shape then its volume can be written as:

V = Width * Length * Depth

Let's call:

w = width

l = length

d = depth.

So we know from the statement of the problem that:

d = d

w = 5 + 5d              (5 feet more than 5 times the depth)

l = 50 + 5d              (50 feet more than 5 times the depth)

Then, the volume can be written according to the depth as:

V = d(5 + 5d)(50 + 5d)

V = d[250 + 25d + 250d + 25d ^ 2]

V = 25d ^ 3 + 275d ^ 2 + 250d

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Answer:

D.

Step-by-step explanation:

Standard Form (Quadratic): y=ax^2+bx+c

Vertex Form (Quadratic): y=a(x-h)^2+k

Intercept Form (Quadratic): y=a(x-p)(x-q)

      p,q are x-intercepts

x-intercepts given in graph: -2,4

y=a[x-(-2)](x-4)

eqn 1: y=a(x+2)(x-4)

Plug in the given point to find 'a' : (3,-5)

-5=a(3+2)(3-4)

-5=a(5)(-1)

1=a

Substitute 'a' in to eqn 1.

y=1(x+2)(x-4)

eqn 2: y=(x+2)(x-4)

Expand eqn 2. (can use FOIL)

y=x^2-2x-8

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3 years ago
Round 19.3 to the nearest whole number
Flura [38]
If the decimal is less than 5 then round down
if the decimal is 5 or more then round up

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19.0 is the answer
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3 years ago
Read 2 more answers
If f(x) = 4x + 1 and g(x) = 2x – 3, then (g(f(x)) =
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Answer g(x)=x2 + 2

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
4) Solve ∆ABC, a = 2.5 cm, c = 3.6 cm, and ∠A = 43°. Begin by sketching and labelling
mezya [45]

The length of b and angle B and C are 3cm, 45  degrees and 79 degrees respectively.

<h3>How to determine the parameters</h3>

To determine the angles and length of sides, we use the sine rule

The sine rule is thus:

\frac{sin A}{a} = \frac{sin B}{b} = \frac{sin C}{c}

Given;

  • a = 2. 5cm
  • c = 3. 6cm
  • ∠A = 43°

Let's find angle C

\frac{sin 43}{2. 5} = \frac{sin C}{3. 6}

cross multiply

0. 682 × 3. 6 = sin C × 2. 5

sin C = 2. 4552/ 2. 5

C = sin^-^1(0. 982)

C = 79°

To find length of b

b= \sqrt{c^2 - a^2}

substitute the values

b = \sqrt{3.6^2 - 2. 5^2}

b = \sqrt{6. 71}

b = 2. 59 cm

b = 3cm

To find angle B, we have

\frac{sin 43}{2. 5} = \frac{sin B}{2. 59}

cross multiply

0. 682 × 2. 59= sin B × 2. 5

sin B = 0. 7065

B = sin^-^1(0. 7065)

B = 45°

Hence, the length of b and angle B and C are 3cm, 45  degrees and 79 degrees respectively.

Learn more about sine rule here:

brainly.com/question/12827625

#SPJ1

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2 years ago
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