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12345 [234]
2 years ago
5

Simplify a trigonometric expression using basic identities.

Mathematics
1 answer:
Sladkaya [172]2 years ago
7 0

Answer:

I will study about it and tell u

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Draw the angle given in degrees on the unit circle where 0 radians corresponds to the positive portion of the horizontal axis: 2
vivado [14]
Ur answer will c as I Claus
4 0
3 years ago
Read 2 more answers
F(x)= 2x^3- x^2 +x+ 1 is divided by 2x +1.
ololo11 [35]

Answer:

Step-by-step explanation:

               x^2

           --------------------------------------------------

2x + 1  /  2x^3     -     x^2    +      x      +    1

               2x^3    +    x^2

              -----------------------

                                    0 + x + 1

                                        x + 1

The quotient is  x^2 + ------------

                                       2x + 1

8 0
3 years ago
Reflect each point in the x-axis and y-axis
Vilka [71]

Step-by-step explanation:

1. x: (-12, -13) y: (12, 13)

2. x: (4 ,9) y: (-4, -9)

3. x: (-10, 8) y: (10, -8)

7 0
3 years ago
Read 2 more answers
5.
Marysya12 [62]
The function has a maximum at (1, 3).

_____
You know it is not a minimum because the coefficient of the squared term is negative.

You know the vertex is (1, 3) because you match the pattern to
.. y = a(x -h)^2 +k
which has its vertex at (h, k).

3 0
3 years ago
Directions: Complete all 3 questions. Make sure you include a graph, work and conclusion.
Simora [160]

Prove that the quadrilateral whose vertices are I(-2,3), J(2,6), K(7,6), and L(3, 3) is a rhombus.

I think in these problems the first step is to express each side as a vector.  A vector is the difference between points.  When two sides have the same vector (or negatives) it means they're parallel and congruent.  So in a rhombus IJKL the vectors IJ and LK should be the same, as should JK and IL.  That much assures a parallelogram; we check IJ and JK are congruent to complete the crowing of the rhombus.

Let's calculate these vectors:

IJ = J - I = (2,6) - (-2,3) = (2 - -2, 6 - 3) = (4, 3)

LK = K - L = (7, 6) - (3, 3) = (4, 3)

IJ = LK, so far so good

(Note: If you haven't got to vectors yet you can just show the two sides are the same length, 5, and have the same slope, 3/4, both of which can be read off the vectors.)

JK = K - J = (7,6) - (2,6) = (5,0)

IL = L - I = (3, 3) - (-2, 3)  = (5, 0)

Those are the same too.    

Now we have to show IJ ≅ JK

The length of IJ is the cliche √4²+3² = 5, the same as JK, so IJ ≅ JK

We showed all four sides are congruent and we have two pair of parallel sides, so we have a rhombus.

8 0
3 years ago
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