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3 years ago

Help would be really nice here just a bit lost

Mathematics

1 answer:

Fantom [35]3 years ago

7 0

Subtract 3 from 3 and 6
Then multiply by -2 on both sides

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In part 3.2.2 of the experiment, a pair of students measure theta mirror= 20 degrees. to find theta bench , they use the theoret

Roman55 [17]

Θ=20
sinθm=1/2sinθb
Θ=47
sin20 mirror=1/2sin47bench

8 0

3 years ago

25/75 = x/15 what is x

liq [111]

Answer:

x=5

Step-by-step explanation:

8 0

3 years ago

Math question down below

Alchen [17]

the answer will be 36

4 0

3 years ago

Read 2 more answers

A, B, and C are points on the circumference of a circle, centre 0. AOB is a diameter of the circle. Prove that angle ACB is 90°

ki77a [65]

Answer:

Kindly refer to explanation.

Step-by-step explanation:

Given that:

A,B and C are 3 points on circumference of circle with centre O.

AOB is diameter.

Kindly refer to the attached image.

To prove:

$\angle ACB = 90^\circ$

Solution:

Let $\angle A = x$ and $\angle B = y$ .

<em>Construction</em>: Join point A with centre O.

Considering $\triangle AOC$ :

Side AO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, $\angle ACO=\angle A=x$

Considering $\triangle BOC$ :

Side BO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, $\angle BCO=\angle B=y$

$\angle ACB = \angle ACO + \angle BCO = x+y$ ...... (1)

Now, in $\triangle ABC:$

Using angle sum property of triangle:

$\angle A + \angle B + \angle ACB =180^\circ\\\Rightarrow x+y+x+y=180^\circ\\\Rightarrow 2(x+y)=180^\circ\\\Rightarrow x+y=90^\circ$

By equation (1):

$\angle ACB = 90^\circ$

Hence proved.

5 0

3 years ago

3(7x+4) very confused helppppppppp

Gnom [1K]

Answer:

21x + 12

Step-by-step explanation:

Distribute

3(7x) = 21x 3(4) = 12

21x + 12

So that’s the answer cuz like terms cannot b combined with numbers

7 0

3 years ago

Read 2 more answers