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Zinaida [17]
3 years ago
15

What are the domain and range of the function?

Mathematics
1 answer:
galben [10]3 years ago
3 0
The answer is b life goes on

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What is the missing value in the solution to the equation. y=3x-7
nikitadnepr [17]

Answer:

minus 4

Step-by-step explanation:

y=3x-7

y=3-7

y=-4

(1,-4)

5 0
3 years ago
Which statement is true about this right triangle?
Ludmilka [50]
Y^2 + z^2=x^2

In a right triangle the sum of the sides^2 are equal to the hypotenuse^2
7 0
3 years ago
Solve for x, with variables on both sides of equation. (Note: x is the same thing as 1x) You must show your work!
bagirrra123 [75]
Hello! We already have the equation set up, which is 9x = x + 4. Let's solve for x. Subtract x from both sides to get each side by itself x - x cancels out. 9x - x is 8x. That leaves 8x = 4. Now, divide each side by 8 to isolate the x. 8x/8 cancels out. 4/8 is 4/8 or 1/2 in cimplest form. Let's plug this value in and see if it works. 9 * 1/2 is 4 1/2. 1/2 + 4 is 4 1/2. 4 1/2 = 4 1/2. There. x = 1/2. 
6 0
4 years ago
3a-13=47 a= pls help ive been stuck on this for an hower
patriot [66]

Hey there!

Explanation:

First, you had to do is add by 13 from both sides of an equation.

3a-13+13=47+13

Then, simplify or add by the numbers.

47+13=60

3a=60

Next, you can also divide by 3 from both sides of an equation.

\frac{3a}{3}=\frac{60}{3}

And finally, simplify and divide by the numbers,

60/3=20

*The answer must have a positive sign.*

\boxed{a=20}

Hope this helps!

6 0
3 years ago
Read 2 more answers
How do you identify which quadrant a point is located in?
ArbitrLikvidat [17]

Answer:

1) If both x and y are positive then this point is at quadrant I (it is upper-right quadrant). 2) If x is negative but y is positive then point is at quadrant II (this one is upper-left quadrant). 3) If x and y are negative then point is at quadrant III (lower-left).

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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